我从响应中获得了日期格式
2015-12-23 05:17:04
但是,我想检查日期和时间,
日期==今天? date ==昨天?
时间== 1小时 时间== 2小时至9小时
怎么做?
答案 0 :(得分:2)
要查看日期是今天,昨天,明天等等,您可以使用NSDate-Extensions
例如:
NSDate *date = [self convertStringToDate:@"2015-12-24 12:40:04" formate:@"yyyy-MM-dd HH:mm:ss"];
NSLog(@"%d", [date isToday]);
NSLog(@"%d", [date isTomorrow]);
NSLog(@"%d", [date isYesterday]);
- (NSDate *)convertStringToDate: (NSString *)date formate:(NSString *)formate {
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
[dateFormat setDateFormat:formate];
return [dateFormat dateFromString:date];
}
答案 1 :(得分:1)
NSDate *date = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
dateFormatter.dateFormat = [NSString stringWithFormat:@"yyyyMMddHHmmss"];
NSString *now = [dateFormatter stringFromDate:date];
您可以尝试以上代码
祝福
答案 2 :(得分:1)
使用此方法返回NSString。你可以比较方法中的字符串或时间。
-(NSString* )AgoStringFromTime:(NSDate*)dateTime
{
NSDictionary *timeScale = @{@"sec" :@1,
@"min" :@60,
@"hr" :@3600,
@"day" :@86400,
@"week" :@605800,
@"month":@2629743,
@"year" :@31556926};
NSString *scale;
int timeAgo = 0-(int)[dateTime timeIntervalSinceNow];
if (timeAgo < 60) {
scale = @"sec";
} else if (timeAgo < 3600) {
scale = @"min";
} else if (timeAgo < 86400) {
scale = @"hr";
} else if (timeAgo < 605800) {
scale = @"day";
} else if (timeAgo < 2629743) {
scale = @"week";
} else if (timeAgo < 31556926) {
scale = @"month";
} else {
scale = @"year";
}
timeAgo = timeAgo/[[timeScale objectForKey:scale] integerValue];
NSString *s = @"";
if (timeAgo > 1) {
s = @"s";
}
return [NSString stringWithFormat:@"%d %@%@", timeAgo, scale, s];
}
答案 3 :(得分:1)
1.frist你可以将你的字符串格式化为日期,如下所示:
+ (instancetype)date;//get current
- (NSTimeInterval)timeIntervalSinceDate:(NSDate *)refDate;//Returns the interval between the receiver and another given date.
2.然后,您可以使用NSDate,
的方法HttpSession session = request.getSession();
String sessionid = session.getId();