Question

我有一个[]string retry我内心有一些字符串让我们说： a 2，a 3，h 9，asd 123等。它们都有字母和整数之间的间隔。现在我需要知道字母部分有多长（在这种情况下，“qwe 2”字母长度为3，整数部分为2）。我稍后使用指定索引处的.substring，字母部分结束，整数开始。

string[] s = new string[5];
List<string> retry = new List<string>();
int max = 1;

for (int i = 0; i < s.Length; i++)
{
    s[i] = Console.ReadLine();
}

Console.WriteLine(" ");
Array.Sort(s);

for (int j = 0; j < s.Length; j++)
{
    if (j > 0)
    {
        if (s[j] == s[j - 1])
        {
            max++;

            if (retry.Any(x => x.Contains(s[j])))
            {
                retry.Add(s[j] + " " + max);
            }
            else
            {
                if (j <= s.Length - 1)
                {
                    if (s[j-1] != s[j])
                    {
                        retry.Add(s[j] + " " + max);
                    }
                    else
                    {
                        retry.Add(s[j] + " " + max);
                    }
                }
            }
        }
        else
        {
            max = 1;
        }
    }
}

for (int j = 0; j < retry.ToArray().Length; j++)
{
    for (int k = j + 1; k < retry.ToArray().Length; k++)
    {
        var a1=retry[j].Substring(0,1);
        var a2 = retry[k].Substring(0,1);

        if(a1==a2)
        {
            var b1 = retry[j].Substring(2);
            var b2 = retry[k].Substring(2);

            if(int.Parse(b1)>int.Parse(b2))
            {
                retry.Remove(a2 + " "+ b2);
            }
            else
            {
                retry.Remove(a1 + " " + b1);
            }
        }
    }

    Console.WriteLine(retry[j]);
}

Console.ReadKey();

这仅适用于1个字母。

Answer 1

下面的代码应该按预期得到结果：

string [] entries =  {"xyz 1","q 2","poiuy 4"};
for(int i=0;i<entries.Length;i++)
{
    var parts = entries[i].Split(' ');
    var txtCount = parts[0].Length;
    Console.WriteLine(String.Format("{0} {1}", txtCount, parts[1]));
}

Answer 2

怎么样......

string[] test = new [] { "qwe 2", "a 2", "b 3", "asd 123" };

foreach (var s in test)
{
    var lastLetterIndex = Array.FindLastIndex(s.ToCharArray(), Char.IsLetter);
    var lastNumberIndex = Array.FindLastIndex(s.ToCharArray(), Char.IsNumber);
    Console.WriteLine(s);
    Console.WriteLine("Letter Length : " + (lastLetterIndex + 1));
    Console.WriteLine("Number Length : " + (lastNumberIndex - lastLetterIndex));
}
Console.ReadKey();

Answer 3

这将迭代所有字符串并计算字符的长度，并存储数字的值及其索引。请注意，每次迭代都会丢失此信息，但如果您需要的信息的持续时间超过迭代的持续时间，我会留下您的担心。

int letterLength = 0, number = 0, index = 0;
string[] testString = { "a 2", "a 3", "h 9", "asd 123", "sw", "swa23", "swag 2464" };

foreach (string str in testString)
{
    letterLength = 0;
    index = -1;
    int i = 0;

    for (; i < str.Length; i++)
    {
        char c = str[i];
        if (Char.IsLetter(c)) letterLength++;
        else if (Char.IsNumber(c)) break;
    }

    StringBuilder strBuilder = new StringBuilder();

    for (; i < str.Length; i++)
    {
        char c = str[i];

        if (index == -1) index  = str.IndexOf(c);
        strBuilder.Append(c);

        number = Int32.Parse(strBuilder.ToString());
    }

    Console.WriteLine($"String: {str}\nLetter Length: {letterLength} Number: {number} Index: {index}\n");
}

C＃如何获取字符串

3 个答案: