Question

如何替换/删除此JSON中的某些字符串？。我认为可以使用str_replace方法或preg_replace解决此问题但我不知道如何添加正则表达式

请帮帮我。

这里是我的json

Array
(
    [data] => Array
        (
            [0] => Array
                (
                    [DESC] => bla bal bal
                    [SOLD] => 0
                    [contact_no] => 1234
                    [title] =>  Hiiiii
                    [price] => 10900
                    [big_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/14.jpg
                            [1] => http://example.com/images/user_adv/15.jpg
                        )

                    [small_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/small/14.jpg
                            [1] => http://example.com/images/user_adv/small/15.jpg
                        )

                [tpe] => user
            )

            [1] => Array
                (
                    [DESC] => fo fo fof ofof
                    [SOLD] => 0
                    [contact_no] => 234522
                    [title] => Hellooooo sddf
                    [price] => 0
                    [big_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/154.jpg
                            [1] => http://example.com/images/user_adv/144.jpg
                            [2] => http://example.com/images/user_adv/147.jpg
                        )

                     [small_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/small/154.jpg
                            [1] => http://example.com/images/user_adv/small/144.jpg
                            [2] => http://example.com/images/user_adv/small/147.jpg
                        )

                    [tpe] => user
                )

        )

    [pis] => 3
    [totals] => 23
    [curpage] => 1
    [total_ads] => 71
)

我将使用此函数将json导出到csv

function array_flatten ($nonFlat) {
    $flat = array();
    foreach (new RecursiveIteratorIterator(
            new RecursiveArrayIterator($nonFlat)) as $k=>$v) {
        $flat[$k] = $v;
    }
    return $flat;
}

$fp = fopen("output.csv","w");
foreach ($json['data'] as $fields) {
    fputcsv($fp, array_flatten($fields));
}
fclose($fp);

上面的代码工作正常但每个图片链接都有一列所以看起来很糟糕，我需要在一列上制作每组图片我尝试将正则表达式添加到链接图像的一部分，除了第一个图像url [0]并将另一个与其合并，我可以将它们放在一列中.... 所以对于实验我把它添加到上面的代码但似乎没有发生

 $flat[$k] = str_replace('[1-7] => http', "http", $v);

这里我希望输出类似

....
[big_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/154.jpg
                            http://example.com/images/user_adv/144.jpg
                            http://example.com/images/user_adv/147.jpg
                        )

                    [small_image] => Array
                        (
                            [0] => http://example.com/images/user_adv/small/154.jpg
                            http://example.com/images/user_adv/small/144.jpg
                            http://example.com/images/user_adv/small/147.jpg
                        )
.....

编辑此.csv文件输出如下所示

我希望有类似的东西

Answer 1

好的我已经修复了

foreach (
    new RecursiveArrayIterator($nonFlat) as $k=>$v) {
 $flat[$k] = is_array($v)?implode(" ",$v):$v;

现在我在一列上得到了每组图像

谢谢：）

在PHP中使用regex替换json字符串

1 个答案: