Question

我在从两个不同的sql查询中获取值之间的实际差异时遇到问题。例如：

查询1：

SELECT x from db1 where date = 'mm-dd-yy'

查询2：

SELECT x from db1 where date = 'mm1-dd1-yy'

每个查询返回10个不同的值。我想要一个查询，它返回两个查询中值之间的实际差异（Q1中的Value1 - 来自Q2的Value1，类似于value2，依此类推）尝试EXCEPT，但这不起作用。有什么建议吗？

Answer 1

尝试类似：

Select  x-x2 from
(
(SELECT c1,(case when date = 'mm1-dd1-yy' then c11 end)as x2,x from kdue)
)as y
where date = 'mm1-dd1-yy'

Answer 2

如果我理解你的正确，请看下面的方法，如果它适合你。

select value1_From_QRY1-value1_From_QRY2 from (
   select row_cnt,sum(val1) as value1_From_QRY1,sum(va2) as value1_From_QRY2 from 
    (SELECT ROWNUM as row_cnt,x as val1 ,0 as val2 from db1 where date = 'mm-dd-yy' 
     union all
    SELECT ,ROWNUM ,0,x from db1 where date = 'mm1-dd1-yy')
   group by row_cnt)

Answer 3

SELECT A.x1- B.x2 AS Difference FROM

(

(SELECT c, x1 from db1 where date = 'mm-dd-yy') AS A

JOIN

(SELECT c, x2 from db1 where date = 'mm1-dd1-yy') AS B

ON B.c = A.c

ORDER BY A.c, B.c

两个SQL查询中的值之间的差异

3 个答案: