访问SQL对象内部联接的数据

Question

我正在尝试使用此内部联接来显示输出标题和日期。仅返回提供对象详细信息的sql对象。这是结果。我可以访问num_rows，但只是给我int（11）记录的数量，不知道如何访问字段中的信息。 这是结果。 object（mysqli_result）＃6（5）{[“current_field”] =＆gt; int（0）[“field_count”] =＆gt; int（2）[“lengths”] =＆gt; NULL [“num_rows”] =＆gt; int（11）[“type”] =＆gt; int（0）}

感谢您的帮助。

$sql  = "SELECT  title, artist_name"; 
$sql .= " FROM follows";
$sql .= " INNER JOIN artworks";
$sql .= " ON follows.user_id_followed = artworks.artist_id";
$sql .= " AND follows.user_id_follower='12'";

$result_set = $database->query($sql);

echo var_dump($result_set);

Answer 1

你需要一个WHERE

$sql  = "SELECT  title, artist_name"; 
$sql .= " FROM follows";
$sql .= " INNER JOIN artworks";
$sql .= " ON follows.user_id_followed = artworks.artist_id";
$sql .= " WHERE follows.user_id_follower='12'";

您可能也希望LEFT JOIN不是INNER JOIN`