Question

XML示例：

<?xml version="1.0" encoding="utf-8" ?>
<brand name="brand1" num_brand="118" enabled="True">
  <price>
    <nodePattern>pattern</nodePattern>
    <attribute type="text" ></attribute>
    <treatment enabled="1" type="Regex">reg</treatment>
  </price>
  <title>
    <nodePattern>pattern</nodePattern>
    <attribute type="text" ></attribute>
    <treatment enabled="1" type="Regex">reg</treatment>
  </title>
</brand>

请问，我如何使用System.Xml.Linq获取所有不同节点的不同属性值和文本（例如name，num_brand和enabled for enabled，enabled，type和“reg”for treatment）？

谢谢！

Answer 1

System.Xml.Linq命名空间比System.Xml命名空间好得多。您的XDocument只有一个XElement，而var text = @"<?xml version=""1.0"" encoding=""utf-8"" ?> <brand name=""brand1"" num_brand=""118"" enabled=""True""> <price> <nodePattern>pattern</nodePattern> <attribute type=""text"" ></attribute> <treatment enabled=""1"" type=""Regex"">reg</treatment> </price> <title> <nodePattern>pattern</nodePattern> <attribute type=""text"" ></attribute> <treatment enabled=""1"" type=""Regex"">reg</treatment> </title> </brand>"; XDocument document = XDocument.Parse(text); // one root element - "brand" System.Diagnostics.Debug.Assert(document.Elements().Count() == 1); XElement brand = document.Element("brand"); // brand has two children - price and title foreach (var element in brand.Elements()) Console.WriteLine("element name: " + element.Name); // brand has three attributes foreach (var attr in brand.Attributes()) Console.WriteLine("attribute name: " + attr.Name + ", value: " + attr.Value);则包含子元素。每个元素都有属性和值。

以下是您的示例：

bsdb::instance()

Answer 2

你有很多方法可以做到这一点。其中一个是XmlDocument。

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(myXML);
foreach(XmlNode node in xmlDoc.DocumentElement.ChildNodes){
    string text = node.InnerText; //you can loop through children
}

看一下这篇文章： How do I read and parse an XML file in C#?

Personnaly我喜欢Linq To Xml方法，这里有更多信息： https://msdn.microsoft.com/en-us/library/bb387061.aspx

Answer 3

试试这个

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENMAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENMAME);

            var brand = doc.Descendants("brand").Select(x => new
            {
                name = x.Attribute("name").Value,
                num_brand = x.Attribute("num_brand").Value,
                enabled = x.Attribute("enabled").Value,
                nodePattern = x.Element("price").Element("nodePattern").Value,
                attribute = x.Element("price").Element("attribute").Attribute("type").Value,
                priceTreatmentEnable = x.Element("price").Element("treatment").Attribute("enabled").Value,
                priceTreatmentType = x.Element("price").Element("treatment").Attribute("type").Value,
                priceTreatment = x.Element("price").Element("treatment").Value,
                titleTreatmentEnable = x.Element("title").Element("treatment").Attribute("enabled").Value,
                titleTreatmentType = x.Element("title").Element("treatment").Attribute("type").Value,
                titleTreatment = x.Element("title").Element("treatment").Value
            }).FirstOrDefault();
        }
    }
}

如何在XML中获取文本和属性值

3 个答案: