Question

我正在尝试创建一份报告，向我显示客户提交票证的最后日期。

客户可以提交数十张门票。我想知道最后一张票的提交时间，并显示自从他们这样做了多少天。

我拥有的字段是：

客户，

Ticket_id，

Date_Closed

所有来自同一张表“门票”

我想我想在最后约会时对门票进行排名？我尝试了这个查询来获取一些东西，但它给了我所有客户的门票。（我在名为Domo的产品中使用SQL）

select * from (select *, rank() over (partition by "Ticket_id" 
                order by "Date_Closed" desc) as date_order
from tickets ) zd
where date_order = 1

Answer 1

这应该很简单，

Runnable

Answer 2

select Customer, datediff(day, date_closed, current_date) as days_since_last_tkt
from 
(select *, rank() over (partition by Customer order by "Date_Closed" desc) as date_order
from tickets) zd
join tickets t on zd.date_closed = t.date_closed
where zd.date_order = 1

或者你可以简单地做

select customer, datediff(day, max(Date_closed), current_date) as days_since_last_tkt
from tickets
group by customer

选择其他字段

select t.* 
from tickets t
join (select customer, max(Date_closed) as mxdate,
      datediff(day, max(Date_closed), current_date) as days_since_last_tkt
      from tickets
      group by customer) tt 
on t.customer = tt.customer and tt.mxdate = t.date_closed

Answer 3

我会用一个简单的子查询来选择客户的最后一个截止日期。然后将此与今天Select LastTicket.Customer, LastTicket.LastClosedDate, DateDiff(day,LastTicket.LastClosedDate,getdate()) as DaysSinceLastClosed From (select tickets.customer max(tickets.dateClosed) as LastClosedDate from tickets Group By tickets.Customer) as LastTicket进行比较，以获得自上次关闭以来的天数。

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Answer 4

根据回复，这就是我所做的：

select "Customer",
Max("date_closed") "last_date,

round(datediff(DAY, CURRENT_DATE, max("date_closed")), 0) as "Closed_date"

from tickets

group by "Customer"
ORDER BY "Customer"

自上次帮助故障单上的天数被提起

4 个答案: