Question

阅读下面的python dict或其等效的yaml并生成等效的python函数调用

mydict = {'RouteAdd': {'route_config': {'RouteConfig': {'table_name': 'my table', 'app_id': 'my app', 'nexthops': [{'NexthopInfo': {'nexthop_index': 2, 'nexthop_address': {'GatewayAddress': {'ethernet_mac': 'my mac', 'nexthop_ip': 'my ip'}}, 'if_name': 'my interface'}}]}}}}

它的yaml（为了便于阅读）：

RouteAdd:
  route_config:
    RouteConfig:
      app_id: "my app"
      nexthops:
      - NexthopInfo:
          if_name: "my interface"
          nexthop_address:
            GatewayAddress:
              ethernet_mac: "my mac"
              nexthop_ip: "my ip"
          nexthop_index: 2
      table_name: "my table"

我想阅读上面的yaml或python dict，并调用如下：

RouteAdd(route_config=Routeconfig(app_id="my app",nexthops=[NexthopInfo(if_name="my interface",nexthop_address=GatewayAddress(ethernet_mac="my mac",nexthop_ip="my ip"),nexthop_index=2)],table_name="my table"))

基本上，备用层次结构是一个对象。我粘贴的是一个小剪辑。寻找一个递归函数，通过读取yaml或python dict并将其转换为上面的格式来执行此操作，以便我可以调用并执行该函数。任何帮助深表感谢。谢谢

Answer 1

试试这个：

def call_dict(d):
    k, v = list(d.items())[0]  # ('RouteAdd', {route_config: ...})
    kwargs = {}
    for k2, v2 in v.items():
        if isinstance(v2, dict):
            kwargs[k2] = call_dict(v2)
        elif isinstance(v2, list):
            kwargs[k2] = [(call_dict(v3) if isinstance(v3, dict) else v3) for v3 in v2]
        else:
            kwargs[k2] = v2
    return globals()[k](**kwargs)

测试：

def test1(t_arg=None, t_arg2=None):
    return t_arg + sum(t_arg2)

def test2(t_arg=None):
    return t_arg


res = test1(t_arg=1, t_arg2=[test2(t_arg=2), test2(t_arg=3)])
print(res)  # 6


test_dict = {
    'test1': {
        't_arg': 1,
        't_arg2': [
            {'test2': {'t_arg': 2}},
            {'test2': {'t_arg': 3}},
        ]
    }
}

res = call_dict(test_dict)
print(res)  # 6

<强> UPD：

作为代码串：

def str_of_code(d):
    k, v = list(d.items())[0]
    kwargs = {}
    for k2, v2 in v.items():
        if isinstance(v2, dict):
            kwargs[k2] = str_of_code(v2)
        elif isinstance(v2, list):
            kwargs[k2] = '[{}]'.format(', '.join(
                (str_of_code(v3) if isinstance(v3, dict) else repr(v3)) for v3 in v2)
            )
        else:
            kwargs[k2] = repr(v2)
    return '{}({})'.format(k, ', '.join('{}={}'.format(*i) for i in kwargs.items()))


test_dict = {
    'test1': {
        't_arg': 1,
        't_arg2': [
            {'test2': {'t_arg': 2}},
            {'test2': {'t_arg': 3}},
        ]
    }
}

res = str_of_code(test_dict)
print(res)  # test1(t_arg=1, t_arg2=[test2(t_arg=2), test2(t_arg=3)])

Answer 2

尝试了论坛中建议的所有可用方法，但不知何故没有人为我正在寻找的解决方案而努力。因此，作为初学者，通过以下非传统的寻找和替换方式解决了它。如果有人有更好的解决方案，请发布，我想使用它。

api_map_complete = {api: {'config': {'AddressConfig': {'unit': 0, 'port_name': "my_name", 'address': "my address", 'family': 2}}}} 

def dict_to_obj(mystr,flag):
    global api_string
    if re.search(':\(',mystr):    
        if flag % 2 == 0:    
            api_string=mystr.replace(":(","(",1)
            flag=flag+1
        else:
            api_string=mystr.replace(":("," = (",1)
            flag=flag+1
        dict_to_obj(api_string,flag)
    else:    
        mystr=mystr.replace(":"," = ")
        mystr=mystr.replace(",",", ")
        api_string=mystr    

for combo in api_map_complete:    

    api_name=combo.keys()[0]
    for k,v in combo.iteritems():
        api_string=str(v)
        api_string=api_string.replace("{","(")
        api_string=api_string.replace("}",")")
        api_string=api_string.replace(" ","")
        api_string=api_string.replace(":'",":\"")
        api_string=api_string.replace("',","\",")
        api_string=api_string.replace("')","\")")
        api_string=api_string.replace("'","")
        dict_to_obj(api_string,1)
    #print api_string
    api_obj=api_name+api_string
    print api_obj

读取python dict或yaml并使用参数和对象调用python函数

2 个答案: