Question

以下是在KnockoutJS中使用nestedSortable显示为template的树。

到目前为止，我有一棵树可以工作，但我找不到一种有效的方法来检查鼠标拖动造成的变化。

解决方案应该允许在拖动节点时检查更改事件（跟踪更改是保存或更新数据所必需的）。它应该能够确定树中发生的变化。

感兴趣的属性将是移动的节点的id，id的新（和原始）父级。

如何正确监控鼠标事件，例如使用此类可排序鼠标拖动？

function Node(data) {
  var self = this;
  typeof data != 'undefined' ? self.id = data.id : self.id = '1';
  self.parent = ko.observable();
  self.children = ko.observableArray();
  self.addNode = function() {
    var child = new Node({
      'id': self.id + '.' + (self.children().length + 1)
    });
    child.parent(self);
    self.children.push(child);
    return child;
  }
};
var tree = new Node();
var child1 = tree.addNode();
var child11 = child1.addNode();
var child12 = child1.addNode();
var child2 = tree.addNode();
var child21 = child2.addNode();
var child3 = tree.addNode();
var viewModel = function() {
  this.tree = ko.observable(tree);
};
ko.applyBindings(new viewModel());

$('.sortable')
  .nestedSortable({
    startCollapsed: false
  });

ol.sortable,
ol.sortable ol {
  margin: 0 0 0 25px;
  padding: 0;
  list-style-type: none;
}
ol.sortable {
  margin: 4em 0;
}
.sortable li {
  margin: 5px 0 0 0;
  padding: 0;
}
.sortable li div {
  border: 1px solid #d4d4d4;
  cursor: move;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.js"></script>
<script src="https://cdn.rawgit.com/furf/jquery-ui-touch-punch/master/jquery.ui.touch-punch.min.js"></script>
<script src="https://cdn.rawgit.com/mjsarfatti/nestedSortable/master/jquery.mjs.nestedSortable.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.2.0/knockout-min.js"></script>

<div class="dd" data-bind="template: {name:'nodeTemplate', data: tree}"></div>
<script id='nodeTemplate' type='text/html'>
  <div data-bind="text: id"></div>
  </div>
  <ol class="sortable ui-sortable" data-bind="foreach: { data: children, as: 'child' }">
    <li data-bind="template: {name:'nodeTemplate', data: child}, attr: { 'data-id': child.id }">
    </li>
  </ol>
</script>

Answer 1

这只是一个方向。您可以使用＆＃34; parent＆＃34; Sortable Widget

可排序窗口小部件的"stop"事件可能对您有帮助吗？

＆＃13;

var size = 5;
var navigationItems = {};
navigationItems['id'] = 'list_' + (i + 1);
navigationItems['displayLabel'] = 'list_' + (i + 1);
navigationItems['children'] = new Array(size);
for (var i = 0; i < size; i++) {
  navigationItems['children'][i] = {};
  navigationItems['children'][i]['id'] = 'list_' + (i + 1) + ".1";
  navigationItems['children'][i]['displayLabel'] = 'list_' + (i + 1) + ".1";
  navigationItems['children'][i]['children'] = new Array(1);
  navigationItems['children'][i]['children'][0] = {};
  navigationItems['children'][i]['children'][0]['id'] = 'list_' + (i + 1) + ".1.1";
  navigationItems['children'][i]['children'][0]['displayLabel'] = 'list_' + (i + 1) + ".1.1";
  navigationItems['children'][i]['children'][0]['children'] = new Array(0);
};
var viewModel = function() {
  this.tree = ko.observable();
};
var viewModelInstance = new viewModel();
viewModelInstance.tree(navigationItems);
ko.applyBindings(viewModelInstance);

var stopHandler = function(args) {
    var model = ko.dataFor(args.target);
    alert(model.id);
};
$('.sortable')
  .nestedSortable({
    startCollapsed: false,
    stop: stopHandler
  });

＆＃13;

ol.sortable,
ol.sortable ol {
  margin: 0 0 0 25px;
  padding: 0;
  list-style-type: none;
}
ol.sortable {
  margin: 4em 0;
}
.sortable li {
  margin: 5px 0 0 0;
  padding: 0;
}
.sortable li div {
  border: 1px solid #d4d4d4;
  cursor: move;
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.js"></script>
<script src="https://cdn.rawgit.com/furf/jquery-ui-touch-punch/master/jquery.ui.touch-punch.min.js"></script>
<script src="https://cdn.rawgit.com/mjsarfatti/nestedSortable/master/jquery.mjs.nestedSortable.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.2.0/knockout-min.js"></script>

<div class="dd" data-bind="template: {name:'nodeTemplate', data: tree}"></div>
<script id='nodeTemplate' type='text/html'>
  <div data-bind="text: displayLabel"></div>
  </div>
  <ol class="sortable ui-sortable" data-bind="foreach: { data: children, as: 'child' }">
    <!-- ko if: child.children.length > 0 -->
    <li class="mjs-nestedSortable-expanded mjs-nestedSortable-branch" data-bind="template: {name:'nodeTemplate', data: child}, attr: { 'data-id': child.id }">
    </li>
    <!-- /ko -->
    <!-- ko if: child.children.length == 0 -->
    <li class="mjs-nestedSortable-leaf" data-bind="template: {name:'nodeTemplate', data: child}, attr: { 'data-id': child.id }">
    </li>
    <!-- /ko -->
  </ol>
</script>

＆＃13;

KnockoutJS：检查嵌套sortable中的项目是否已重新排序

1 个答案: