Question

我有一个用于创建表格和相关结构的脚本

DROP TABLE CDR.ExtDL_JobStatus;

-- 
-- TABLE: CDR.ExtDL_JobStatus 
--

CREATE TABLE CDR.ExtDL_JobStatus(
    Id             NUMBER(38, 0)    NOT NULL,
    ShortName      NUMBER(38, 0)    NOT NULL,
    Description    NUMBER(38, 0)    NOT NULL,
    CONSTRAINT PK_ExtDL_JobStatus PRIMARY KEY (Id)
)
;



SHOW ERRORS;
Declare NumOfSequences NUMBER :=0;
Begin
  Select COUNT(*)
  INTO NumOfSequences
  FROM All_Sequences
  WHERE 1=1
    And upper (Sequence_Owner) = upper ('CDR')
    And upper (Sequence_Name) = upper ('ExtDL_JobStatus_Seq');
  If NumOfSequences > 0 Then
    Execute IMMEDIATE 'DROP SEQUENCE CDR.ExtDL_JobStatus_Seq';
  End If;
End;
/
CREATE SEQUENCE CDR.ExtDL_JobStatus_Seq
    INCREMENT BY 1
    START WITH 1
    NOMAXVALUE 
    NOMINVALUE 
;
/

SHOW ERRORS;
Declare NumOfTriggers NUMBER :=0;
Begin
  SELECT COUNT(*)
  INTO NumOfTriggers
  FROM All_Triggers
  WHERE 1=1
    And upper (Owner) = upper ('CDR')
    And upper (Trigger_Name) = upper ('ExtDL_JobStatus_SeqTrg');
  If NumOfTriggers > 0 Then
    Execute IMMEDIATE 'DROP TRIGGER CDR.ExtDL_JobStatus_SeqTrg';
  End If;
End;
/
CREATE TRIGGER CDR.ExtDL_JobStatus_SeqTrg
BEFORE INSERT
ON CDR.ExtDL_JobStatus
    FOR EACH ROW
    WHEN (new.Id IS NULL)
    BEGIN
        SELECT ExtDL_JobStatus_Seq.nextval into :new.Id from dual;
    END;


/
SHOW ERRORS;


insert into CDR.ExtDL_JobStatus (SHORTNAME, Description) VALUES (1, 1);
insert into CDR.ExtDL_JobStatus (SHORTNAME, Description) VALUES (1, 1);
insert into CDR.ExtDL_JobStatus (SHORTNAME, Description) VALUES (1, 1);
select * FROM CDR.ExtDL_JobStatus

当我使用 SHOW ERRORS （有多个存在的地方）运行它时，它只会创建表并完成。

DROP TABLE CDR.ExtDL_JobStatus succeeded.
CREATE TABLE succeeded.

当我删除所有显示错误时，这里是返回的内容

DROP TABLE CDR.ExtDL_JobStatus succeeded.
CREATE TABLE succeeded.
anonymous block completed
CREATE SEQUENCE succeeded.
anonymous block completed
TRIGGER CDR.ExtDL_JobStatus_SeqTrg Compiled.
1 rows inserted
1 rows inserted
1 rows inserted
ID                     SHORTNAME              DESCRIPTION            
---------------------- ---------------------- ---------------------- 
1                      1                      1                      
2                      1                      1                      
3                      1                      1                      

3 rows selected

为什么在第一种情况下使用 SHOW ERRORS 终止执行？

Answer 1

尝试删除';'在每次SHOW ERRORS之后。

SET，SHOW ERRORS等SQL * Plus命令不需要;并且有可能存在;可能正在重新运行缓冲区中的前一个命令（即CREATE SEQUENCE），这将导致“对象已存在”错误。（我觉得稍微懒得启动Oracle只是为了证实这一点。）

就个人而言，我总是指定完整的命令 - 即。

SHOW ERRORS TRIGGER ExtDL_JobStatus_SeqTrg

SHOW ERRORS终止执行

1 个答案: