Question

我有$user = wp_get_current_user();数组。当我打印它时会显示

WP_User Object
(
    [data] => stdClass Object
        (
            [ID] => 169 // I wanted the Value of ID
            [user_login] => madhuri@gmail.com
            [user_pass] => $P$BN2ibVoWTXB1DIsdcTnpVV03DBz8od0
            [user_nicename] => madhurigmail-com
            [user_email] => madhuri@gmail.com
            [user_url] => 
            [user_registered] => 2015-11-17 09:54:57
            [user_activation_key] => 
            [user_status] => 0
            [display_name] => Madhuri Kashid
            [latitude] => 
            [longitude] => 
            [role] => 
        )

我只想要ID的值。我想将ID的商店值转换为$UserId 提前致谢

Answer 1

你得对象不是数组

尝试

# -*- coding: utf-8 -*-
from django.conf.urls import url
from django.utils.translation import ugettext_lazy as _
from django.views.generic.base import TemplateView

urlpatterns = [
    url(r'^$', TemplateView.as_view(template_name="index.html"), name='home'),
    url(_(r'^privacy-policy/$'), TemplateView.as_view(template_name="privacy-policy.html"), name='privacy-policy'),
]

Answer 2

根据我的评论，要访问对象内的属性，请使用＆＃39; - ＆gt;＆＃39;操作

$UserId = $user->data->ID;

Answer 3

这是一个对象。因此，$UserId = $user->data->ID; 如果要将其作为数组访问，请先将其类型转换为数组， $array = (array) $user;$user_id = $array['data']['ID'];

从数组中获取Id的值

3 个答案: