我有一个类似下面的数组
1 => "Los Angeles"
2 => "California"
3 => "St. Louis"
4 => "Missouri"
5 => "Boston"
6 => "Massachusetts"
我想将其更改为关联数组,因此每个奇数条目索引都是City,每个偶数条目都是state。 如果这是有道理的,请告诉我。
答案 0 :(得分:1)
此解决方案适合您
<?php
$myarray = array("1" => "Los Angeles" ,
"2" => "California" ,
"3" => "St. Louis" ,
"4" => "Missouri" ,
"5" => "Boston" ,
"6" => "Massachusetts");
var_dump($myarray);
?>
RESULT-array(6){[1] =&gt; string(11)“洛杉矶”[2] =&gt; string(10)“California”[3] =&gt; string(9)“St. Louis”[4] =&gt; string(8)“Missouri”[5] =&gt; string(6)“Boston”[6] =&gt; string(13)“Massachusetts”}
答案 1 :(得分:0)
数组键的名称不能相同。他们必须是&#39; city1&#39;,&#39; city2&#39;等等
答案 2 :(得分:0)
根据您输入的标题,您希望拥有关联数组,但您希望所有索引都相同,这是不可能的。阅读超出你的问题的行,如果我理解正确,你的数组中的所有奇数项目都是城市,甚至项目是州,你想分开它?然后尝试下面:
jacoco {
toolVersion = "0.7.1.201405082137"
}
def coverageSourceDirs = {
'../app/src'
}
task jacocoTestReport(type: org.gradle.testing.jacoco.tasks.JacocoReport, dependsOn: "test"){
group = "Reporting"
description = "Generate Jacoco coverage reports"
classDirectories = fileTree(
dir: '../app/build/intermediates/classes',
excludes: ['**/R.class',
'**/R$.class',
'**/*$ViewInjector*.*',
'**/BuildConfig.*',
'**/Manifest*.*']
)
additionalSourceDirs = files(coverageSourceDirs)
sourceDirectories = files(coverageSourceDirs)
executionData = files('../app/build/jacoco/testDebugUnitTest.exec')
reports {
xml.enabled = true
html.enabled = true
}
}
输出:
<?php
$scrambled_city_state = array(
1 => "Los Angeles",
2 => "California",
3 => "St. Louis",
4 => "Missouri",
5 => "Boston",
6 => "Massachusetts"
);
$cities = array();
$states = array();
foreach ($scrambled_city_state as $key => $city_state) {
if ($key % 2 == 0) {
// state
$states[] = $city_state;
}
else {
// city
$cities[] = $city_state;
}
}
var_dump($cities, $states);
?>