if else语句中的死分支

时间:2015-12-21 23:49:46

标签: java if-statement switch-statement case naming

我正在编写此代码,您可以为程序命名。

Java告诉我,如果变量“isACoolGuy”为false,则应该使用语句中的else。

if (isACoolGuy = true){
        System.out.println("Thank you for this name... "+ name);
    }else if(isACoolGuy = false){    
        System.out.println("Okay im changing my name since you are an idiot");
        name = name = "jack";
        System.out.println("My name is "+ name + " now");

之前有一个switch语句应该将“isACoolGuy”布尔值更改为false。

case "name":
            System.out.println("You are an a******");
            isACoolGuy = false;
            break;

3 个答案:

答案 0 :(得分:3)

你的错误

if (isACoolGuy == true){
        System.out.println("Thank you for this name... "+ name);
    }else if(isACoolGuy == false){
        System.out.println("Okay im changing my name since you are an idiot");
        name = "jack";
        System.out.println("My name is "+ name + " now");

或更好

if (isACoolGuy){
        System.out.println("Thank you for this name... "+ name);
    }else if(!isACoolGuy){
        System.out.println("Okay im changing my name since you are an idiot");
        name =  "jack";
        System.out.println("My name is "+ name + " now");

并且在你的情况下最正确的方法是跳过else if并将其替换为像这样的其他

if (isACoolGuy){
        System.out.println("Thank you for this name... "+ name);
    }else {
        System.out.println("Okay im changing my name since you are an idiot");
        name =  "jack";
        System.out.println("My name is "+ name + " now");

和一些理论

isACoolGuy = true表示为isACoolGuy变量赋值true。 在if中使用它总是返回true isACoolGuy == true检查变量isACoolGuy是否具有true值。 这是比较

在if中你可以跳过比较布尔值,因为if具有以下格式

if(true)
{

}

所以如果(isACoolGuy)类似于if(isACoolGuy == true)

答案 1 :(得分:1)

不是检查它是否为真,而是将isACoolGuy指定为true,因此它总是计算为true。

 if (isACoolGuy = true){

改为使用

 if (isACoolGuy == true){

更好用: -

if (isACoolGuy)

答案 2 :(得分:0)

要检查条件,请使用==而非=进行分配,例如此if(isACoolGuy == true)
尝试删除第二个条件if(isACoolGuy == false)没有必要,这就足以让关键字else像这样:

  isACoolGuy = true;  
  ...
  if (isACoolGuy){ // the positive control
    System.out.println("Thank you for this name... "+ name);
 }else{    // otherwise negative
    ...
  }