Question

我有一个非常基本的Webview应用程序，我正在使用Parse.com发送JSON推送通知。我正在发送带有网址的JSON推送通知，以便在我的网络视图中打开，如下所示：

{
"alert": "Push Title goes here",
"url": "http://www.google.com"
}

当我发送上述消息时，如果应用程序已关闭或在后台，它会显示横幅通知，如果您点按通知，则会打开我们的应用并指示您转到指定的网址。

但是，如果应用程序位于前台，它只会自动加载指定的网址而不进行交互，如果说它们正在检出并且推送的网址意外地将其从结帐页面带走，则可能会出现问题。

理想情况下，我们希望弹出一个包含通知的提醒，并选择点击“查看”以加载网址，或选择“关闭”，这将关闭通知并允许用户继续浏览应用程序他们在哪里。

以下是我目前的情况：

AppDelegate.m

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
[Parse setApplicationId:@"XXX"
              clientKey:@"XXX"];

// Register for Push Notitications

UIUserNotificationType userNotificationTypes = (UIUserNotificationTypeAlert |
                                                UIUserNotificationTypeBadge |
                                                UIUserNotificationTypeSound);
UIUserNotificationSettings *settings = [UIUserNotificationSettings settingsForTypes:userNotificationTypes
                                                                         categories:nil];
[application registerUserNotificationSettings:settings];
[application registerForRemoteNotifications];

// Override point for customization after application launch.

 self.window.rootViewController = self.viewController;
[self.window makeKeyAndVisible];


UILocalNotification *notification = [launchOptions objectForKey:UIApplicationLaunchOptionsRemoteNotificationKey];
NSDictionary *notificationPayload = launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey];
NSString *pushURL = [notificationPayload objectForKey:@"url"];

if (notification) {
    NSDictionary *aDict=[NSDictionary dictionaryWithObject: pushURL forKey:@"urlToLoad"];
    [[NSNotificationCenter defaultCenter] postNotificationName:@"LoadRequestFromAppDel" object:Nil userInfo:aDict];
}

return YES;
}


- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {

NSString *pushURL = [userInfo objectForKey:@"url"];

if (userInfo) {
    NSDictionary *aDict=[NSDictionary dictionaryWithObject: pushURL forKey:@"urlToLoad"];
    [[NSNotificationCenter defaultCenter] postNotificationName:@"LoadRequestFromAppDel" object:Nil userInfo:aDict];
}

}

这是我的 ViewController.m

- (void)viewDidLoad
{
[super viewDidLoad];
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(LoadRequestFromAppDel:) name:@"LoadRequestFromAppDel" object:Nil];

NSAssert(self.back, @"Unconnected IBOutlet 'back'");
NSAssert(self.forward, @"Unconnected IBOutlet 'forward'");
NSAssert(self.refresh, @"Unconnected IBOutlet 'refresh'");
NSAssert(self.stop, @"Unconnected IBOutlet 'stop'");
NSAssert(self.webView, @"Unconnected IBOutlet 'webView'");

self.webView.delegate = self;
self.webView.scalesPageToFit = YES;
NSURL* url = [NSURL URLWithString:@"http://www.myurl.com"];
NSURLRequest* request = [NSURLRequest requestWithURL:url];
[self.webView loadRequest:request];
[self updateButtons];
}

- (void)LoadRequestFromAppDel: (NSNotification*)aNotif
{
NSString *aStrUrl=[[aNotif userInfo] objectForKey:@"urlToLoad"];
NSURL* pushurl = [NSURL URLWithString:aStrUrl];
NSURLRequest* requestObj = [NSURLRequest requestWithURL:pushurl];
[self.webView loadRequest:requestObj];
[self updateButtons];
}

我还会注意到这是我的第一个iOS应用程序，所以我的知识非常有限，但我已经做到了这一点。非常感谢更多的帮助！

Answer 1

您需要向AppDelegate添加额外的方法，以便在应用程序在前台运行时接收通知。从Parse文档：

如果您的应用在收到通知时已经在运行，那么数据在 application:didReceiveRemoteNotification:fetchCompletionHandler: 方法通过userInfo字典。

请参阅：https://www.parse.com/docs/ios/guide#push-notifications-responding-to-the-payload

iOS如何在应用程序处于前台时处理解析JSON推送通知

1 个答案: