Question

问题

我想选择所有数据（行），这些数据（行）位于每天的06:45和07:15之间，为11月10月。

信息

表格中的时间戳格式为：'yyyy-mm-dd hh：mm：ss.000'
记录的每个数据都有一个开始时间戳列（'starts_at'）和一个结束时间戳列（'ends_at'）
我使用convert_tz将'gmt'转换为'us / east'。

使用查询

    select *
    from
      table1
    where
      NOT(
      (hour(convert_tz(starts_at,'gmt','us/eastern')+minute(convert_tz(ends_at,'gmt','us/eastern'))) < 06.45 AND
      (hour(convert_tz(ends_at,'gmt','us/eastern'))+minute(convert_tz(ends_at,'gmt','us/eastern'))) > 07.15
      ) AND
      convert_tz(starts_at,'gmt','us/eastern') > '2015-10-01 00:00:00.000' AND
      convert_tz(ends_at,'gmt','us/eastern') < '2015-12-01 00:00:00.000'
    order by starts_at, ends_at

问题

通过此查询，我获取了整天（从00到23小时）的数据，而不仅仅是我想要的时间段。

编辑1：根据@ GordonLinoff的回答

查询，

select
   convert_tz(starts_at,'gmt','us/pacific') as Starts,
   convert_tz(ends_at,'gmt','us/pacific') as Ends
from
   table1
where
   (100 * hour(convert_tz(starts_at,'gmt','us/pacific'))+minute(convert_tz(starts_at,'gmt','us/pacific'))) >= 0645 AND
   (100 * hour(convert_tz(ends_at,'gmt','us/pacific'))+minute(convert_tz(ends_at,'gmt','us/pacific'))) <= 0715 AND
   convert_tz(starts_at,'gmt','us/pacific') > '2015-12-01 00:00:00.000' AND
   convert_tz(ends_at,'gmt','us/pacific') < '2015-12-20 00:00:00.000' 
order by starts_at, ends_at

响应（前几行的示例仅说明了获取超出范围的时间戳的问题） +-------------------------+-------------------------+ | Starts | Ends | +-------------------------+-------------------------+ | 2015-12-01 06:45:03.549 | 2015-12-01 06:45:35.003 | | 2015-12-01 06:45:35.003 | 2015-12-01 06:47:00.203 | | 2015-12-01 06:47:00.203 | 2015-12-01 06:54:11.615 | | 2015-12-01 06:47:00.780 | 2015-12-01 06:47:40.860 | | 2015-12-01 06:47:40.860 | 2015-12-01 06:48:52.103 | | 2015-12-01 06:48:52.103 | 2015-12-01 06:51:33.925 | | 2015-12-01 06:51:33.925 | 2015-12-01 06:52:34.543 | | 2015-12-01 06:52:34.543 | 2015-12-01 07:00:00.000 | | 2015-12-01 06:54:11.615 | 2015-12-01 06:59:59.074 | | 2015-12-01 06:59:59.074 | 2015-12-01 07:14:59.074 | | 2015-12-01 06:59:59.158 | 2015-12-01 07:14:59.158 | | 2015-12-01 06:59:59.388 | 2015-12-01 07:14:59.388 | | 2015-12-01 06:59:59.393 | 2015-12-01 07:14:59.393 | | 2015-12-01 06:59:59.513 | 2015-12-01 07:14:59.513 | | 2015-12-01 06:59:59.708 | 2015-12-01 07:14:59.708 | | 2015-12-01 07:00:00.000 | 2015-12-01 07:15:00.000 | | 2015-12-01 07:00:00.000 | 2015-12-01 07:15:00.000 | | 2015-12-01 07:00:00.000 | 2015-12-01 07:15:00.000 | | 2015-12-01 07:00:00.000 | 2015-12-01 07:15:00.000 | | 2015-12-01 07:00:01.912 | 2015-12-01 07:14:59.471 | | 2015-12-01 21:59:59.158 | 2015-12-02 00:59:59.158 | | 2015-12-01 21:59:59.388 | 2015-12-02 06:59:59.388 | | 2015-12-01 21:59:59.513 | 2015-12-02 06:59:59.513 | | 2015-12-01 22:00:00.000 | 2015-12-02 01:00:00.000 | | 2015-12-01 22:00:00.000 | 2015-12-02 01:00:00.000 | | 2015-12-01 22:43:26.458 | 2015-12-02 05:13:23.365 | | 2015-12-01 23:15:05.493 | 2015-12-02 05:08:38.585 | | 2015-12-01 23:18:10.110 | 2015-12-02 05:09:29.648 | | 2015-12-01 23:31:41.896 | 2015-12-02 00:10:16.796 | | 2015-12-01 23:45:37.852 | 2015-12-02 00:19:22.301 | | 2015-12-01 23:53:48.851 | 2015-12-02 00:17:20.538 | | 2015-12-02 06:51:11.221 | 2015-12-02 06:51:16.456 | | 2015-12-02 06:51:16.456 | 2015-12-02 07:01:19.435 | 只有2100到0045范围内的时间戳才会在整个数据集中重复出现。

Answer 1

尝试类似：

select *
from
  table1
where
  NOT(
  (time(convert_tz(starts_at,'gmt','us/eastern'))) < '06:45' AND
  (time(convert_tz(ends_at,'gmt','us/eastern'))) > '07:15'
  ) AND
  convert_tz(starts_at,'gmt','us/eastern') > '2015-10-01 00:00:00.000' AND
  convert_tz(ends_at,'gmt','us/eastern') < '2015-12-01 00:00:00.000'
order by starts_at, ends_at

Answer 2

Hour + minute将是0（午夜）和82（23 + 59）之间的值。此外，值不能同时为< 6.45和> 7.15。

有几种方法可以做你想要的。以下是您的方法的要点：

  (100 * hour(convert_tz(starts_at,'gmt','us/eastern')+minute(convert_tz(ends_at,'gmt','us/eastern'))) >= 0645 AND
  (100 * hour(convert_tz(ends_at,'gmt','us/eastern'))+minute(convert_tz(ends_at,'gmt','us/eastern'))) <= 0715
  ) AND

注意没有NOT。这会将小时分钟转换为HHMM形式的数字，可以将其与数字进行比较。

Answer 3

将您的小时数提取并转换为分钟数。

SELECT 
      * 
FROM
     table1
WHERE
      HOURS(starts_at) * 60 + MINUTES(starts_at) >= 405
  And HOURS(ends_at) * 60   + MINUTES(ends_at)   <= 435
order by
starts_at,ends_at

MySQL：在特定时间之间选择数据

问题

信息

使用查询

问题

编辑1：根据@ GordonLinoff的回答

3 个答案: