Question

我正在尝试将Ubuntu上的/etc/network/interfaces文件格式分解为单个节（如手册页所述）。

这是我测试脚本的示例interfaces文件：

# The loopback network interface
auto lo
iface lo inet loopback

auto eth0
iface eth0 inet static
    address 192.168.2.7
    netmask 255.255.255.0
    network 192.168.2.0
    broadcast 192.168.2.255
    gateway 192.0.2.254
    dns-nameservers 12.34.56.78 12.34.56.79

auto eth0:0
allow-hotplug eth0:0
iface eth0:0 inet static
    address 192.168.1.43
    netmask 255.255.255.0

auto eth1
iface eth1 inet dhcp

auto eth2
iface eth2 inet6 static
    address 2001:db8::c0ca:1eaf
    netmask 64
    gateway 2001:db8::1ead:ed:beef

auto br0
iface br0 inet static
    address 10.10.0.15
    netmask 255.255.255.0
    gateway 10.10.0.1
    bridge_ports eth0 eth1
    up /usr/sbin/brctl stp br0 on

我需要的是一系列字符串，包含所有节（iface，mapping，auto，allow-\w+，source(-\w+)?和评论）以及所有节跟随它的文本，直到下一节开始。

我尝试过这样的代码，这听起来应该可行，但它会捕获一个字符串中的所有节：

re.split(r'^(iface|mapping|auto|allow-\w+|source(-\w)?|#.*)[.\n]+?',
    open('/etc/network/interfaces').read(), flags=re.MULTILINE)

如何更正正则表达式以实现此目的？

Python版本是2.7

Answer 1

你不需要正则表达式：

def userr = user.save flush:true

UserRole.create userr, roleUser.findByAuthority('ROLE_USER'), true

输出：

def stanza(fle):
    with open(fle) as f:
        vals = ("iface", "mapping", "auto", "allow-", "source")
        tmp = []
        for line in f:
            if line.startswith(vals):
                yield tmp
                tmp = [line]
            else:
                tmp.append(line)
    if tmp:
        yield tmp


from pprint import pprint as pp
pp(list(stanza("foo.txt")))

如果要删除空白，请使用[['# The loopback network interface\n'], ['auto lo\n'], ['iface lo inet loopback\n', '\n'], ['auto eth0\n'], ['iface eth0 inet static\n', ' address 192.168.2.7\n', ' netmask 255.255.255.0\n', ' network 192.168.2.0\n', ' broadcast 192.168.2.255\n', ' gateway 192.0.2.254\n', ' dns-nameservers 12.34.56.78 12.34.56.79\n', '\n'], ['auto eth0:0\n'], ['allow-hotplug eth0:0\n'], ['iface eth0:0 inet static\n', ' address 192.168.1.43\n', ' netmask 255.255.255.0\n', '\n'], ['auto eth1\n'], ['iface eth1 inet dhcp\n', '\n'], ['auto eth2\n'], ['iface eth2 inet6 static\n', ' address 2001:db8::c0ca:1eaf\n', ' netmask 64\n', ' gateway 2001:db8::1ead:ed:beef\n', '\n'], ['auto br0\n'], ['iface br0 inet static\n', ' address 10.10.0.15\n', ' netmask 255.255.255.0\n', ' gateway 10.10.0.1\n', ' bridge_ports eth0 eth1\n', ' up /usr/sbin/brctl stp br0 on']]将其删除。

如何在Python中使用正则表达式拆分/ etc / network / interfaces

1 个答案: