可选元素按顺序排列

时间:2015-12-19 19:25:01

标签: clojure clojurescript plumatic-schema

我正在尝试使用Prismatic / Schema匹配以下序列:

[{:n "some text"}] ; => valid

[{:k "some text"} {:n "some text"}] ; => valid

我尝试过:

(s/def Elem3
  {:k s/Str})

(s/def Elem2
  {:n s/Str})

(s/def Elem
  [(s/optional Elem2 "elem2") Elem3])

(s/validate Elem [{:k "huji"}])
;; =>
;; Value does not match schema: [(named {:n missing-required-key, :k
;; disallowed-key} "elem2")]

(s/def Elem
  [(s/maybe Elem2) Elem3])

(s/validate Elem [{:k "huji"}])
;; =>
;; [(maybe {:n Str}) {:k java.lang.String}] is not a valid sequence
;; schema; a valid sequence schema consists of zero or more `one`
;; elements, followed by zero or more `optional` elements, followed by
;; an optional schema that will match the remaining elements.

(s/defrecord ElemOption1
  [elem3 :- Elem3])

(s/defrecord ElemOption2
    [elem2 :- Elem2
     elem3 :- Elem3])

(s/def Elem
  (s/conditional
   #(= 2 (count %)) ElemOption2
   :else ElemOption1))

(s/validate Elem [{:k "huji"}])
;; =>
;; Value does not match schema: (not (instance?
;;  peg_dsl.standard_app.ElemOption1 [{:k "huji"}]))

主要问题是我不明白写什么方式 允许省略指定向量的第一个元素的模式。 匹配上述两个向量的正确方法是什么?

1 个答案:

答案 0 :(得分:1)

你第一次尝试的问题是从一开始 可选意味着它期望{:k s / Str}或者没有任何东西,而且它正在看到 {:n s/Str},所以显然不对。

你的第二次尝试有两个问题。 Maybe可以是价值 或nil,但它需要存在。你也没有写过 序列模式正确。但是序列模式的问题 是元素需要按顺序s/one* s/optional*和你 想要s/optional s/one

你的第三次尝试更接近,使用条件,但你是 无法匹配,因为您没有验证的实例 记录,你正在验证地图。

解决方案如下所示:

(def ElemKNList [(s/one {:k s/Str} "k") (s/one {:n s/Str} "n")])
(def ElemNList [(s/one {:n s/Str} "n")])

(def Elem (s/conditional #(= 2 (count %)) ElemKNList 
                         :else ElemNList))

(s/validate Elem [{:k "huji"} {:n "huji"}])    
    => [{:k "huji"} {:n "huji"}]
(s/validate Elem [{:n "huji"}])
    => [{:n "huji"}]          
(s/validate Elem [{:k "huji"}])
    => ExceptionInfo Value does not match schema: [(named {:n missing-required-key, :k disallowed-key} "n")]  schema.core/validator/fn--18435 (core.clj:151)