我的Android应用程序中出现了一个反复出现的问题。
基本上我使用PHP和MYSQL数据库来注册并将用户登录到我的应用程序中。
注册工作正常。我能够连接到数据库并将新用户插入表中而没有任何问题。
我面临的问题是登录应用时。每当我调用登录URL时,我都会收到以下错误:
BasicNetwork.performRequest: Unexpected response code 500 for URL.
我尝试使用其他工具访问此网址并手动发布参数,以消除错误可能来自我的应用代码的问题。事实上我得到了Generic 500 Internal Server Error
。使用此工具测试了注册URL,它运行良好。
我的PHP类都调用相同的脚本来获取连接细节,因此注册工作也没有问题。
以下是我的代码:
登录课程:
<?php
require_once 'UserFunctions.php';
$db = new UserFunctions();
$response = array("error" => FALSE);
if (isset($_POST['email']) && isset($_POST['password'])) {
$email = $_POST['email'];
$password = $_POST['password'];
$user = $db->getUserByEmailAndPassword($email, $password);
$count = $db->getUserCount();
if ($user != false) {
$response["error"] = FALSE;
$response["uid"] = $user["unique_id"];
$response["user"]["name"] = $user["name"];
$response["user"]["email"] = $user["email"];
echo json_encode($response);
} else {
$response["error"] = TRUE;
$response["error_msg"] = "Login credentials are wrong. Please try again!";
echo json_encode($response);
}
} else {
$response["error"] = TRUE;
$response["error_msg"] = "One of the required parameters is missing!";
echo json_encode($response);
}
?>
UserFunctions类:
<?php
class UserFunctions {
private $conn;
function __construct() {
require_once 'include/DbConnect.php';
$db = new DbConnect();
$this->conn = $db->connect();
}
function __destruct() {
}
public function storeUser($name, $email, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$password = $hash["encrypted"];
$salt = $hash["salt"];
$stmt = $this->conn->prepare("INSERT INTO users(unique_id, UserName, UserEmail, UserPassword, salt) VALUES(?, ?, ?, ?, ?)");
$stmt->bind_param("sssss", $uuid, $name, $email, $password, $salt);
$result = $stmt->execute();
$stmt->close();
if ($result) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE UserEmail = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return false;
}
}
public function getUserByEmailAndPassword($email, $password) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE UserEmail = ?");
$stmt->bind_param("s", $email);
if ($stmt->execute()) {
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return NULL;
}
}
public function isUserExisted($email) {
$stmt = $this->conn->prepare("SELECT UserEmail FROM users WHERE UserEmail = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->store_result();
if ($stmt->num_rows > 0) {
$stmt->close();
return true;
} else {
$stmt->close();
return false;
}
}
public function hashSSHA($password) {
$salt = sha1(rand());
$salt = substr($salt, 0, 10);
$encrypted = base64_encode(sha1($password . $salt, true) . $salt);
$hash = array("salt" => $salt, "encrypted" => $encrypted);
return $hash;
}
public function checkhashSSHA($salt, $password) {
$hash = base64_encode(sha1($password . $salt, true) . $salt);
return $hash;
}
}
?>
答案 0 :(得分:2)
我找到了问题所在。
对于遇到非常讨厌的错误500的所有人,请检查您的日志。对我说,一旦我检查了日志,我发现方法checkhashSSHA()
从未被使用过,这导致了以下错误:
PHP Fatal error: Call to undefined function checkHashSSA() in /xxx/xxx/xxx/xxx/UserFunctions.php on line 54
因此我添加了以下代码来解密密码:
public function getUserByEmailAndPassword($email, $password) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE UserEmail = ?");
$stmt->bind_param("s", $email);
if ($stmt->execute()) {
$user = $stmt->get_result()->fetch_assoc();
$salt = $user['salt'];
$userPassword = $user['UserPassword'];
$hash = $this->checkhashSSHA($salt, $password);
if ($userPassword == $hash) {
return $user;
}
$stmt->close();
} else {
return NULL;
}
}
这解决了我的错误。
只是为了记录,这些错误的日志通常位于以下位置:var/log/apache2/error.log
您可能需要对php.ini文件进行一些更改以记录这些错误。
希望这可以帮助任何有500错误的人;)