删除内容之间的额外空间

时间:2015-12-19 07:33:23

标签: jquery html css pagination

enter image description here

两个项目,内容和页脚之间有很多额外的空间 我希望它在内容较少的情况下动态,项目与内容和页脚之间不应有空格。 当数据超过它应该推下分页和页脚相同

这是css

pagination.css

 ul.pagination{
margin-left:670px;
margin-top: 700px;


padding: 75px 0px 0px 0px;

overflow:hidden;
font:12px 'Tahoma';
list-style-type:none;   
}

ul.pagination li.details{
padding:7px 10px 7px 10px;
font-size:14px;
}

 ul.pagination li.dot{padding: 3px 0;}

 ul.pagination li{
float:left;
margin:0px;
padding:0px;
margin-left:5px;
}

ul.pagination li:first-child{
margin-left:0px;
}

ul.pagination li a{
color:black;
display:block;
text-decoration:none;
padding:7px 10px 7px 10px;
}

ul.pagination li a img{
border:none;
}

.item

      border-radius: 25px;
      padding: 20px;
     background-color:white;
    position: absolute;
    margin:10px;
    margin-top:40px;
    margin-left:0px;
    margin-right:10px!important;
    width:  300px;
    height: auto;
    float: left;
    background: #ffff;
    font-size:20px !important;
    text-align:center;
    display: block;
    line-height: 1.42857143;

html

    <div id='masonry'>


      <?php 

        //show records
        $query = mysqli_query($con,"SELECT * FROM {$statement} LIMIT {$startpoint} , {$limit}");

        if($query === FALSE) { 
     die(mysqli_error($db)); // TODO: better error handling
                         }
        $count=1;

        while ($row = mysqli_fetch_assoc($query)) {
            $quote=$row['quote'];
            $name =$row['name'];

    ?>



      <div class="item">

     <?php echo "{$quote}";?><br>
      <?php echo "Author:- {$name}";?>


     </div>


    <?php 
    $count++;
    } 
    ?>

     </div>

   <script src='masonry.pkgd.min.js'></script>
    <script>
    var container = document.querySelector('#masonry');
var masonry = new Masonry(container, {
columnWidth: 50,
   itemSelector: '.item'
     });
     </script>

     <div id = "popular">
     <span> <h3> Popular Author </h3></span>


       <?php
      $query1=mysqli_query($con,"SELECT * FROM `author` WHERE popular = 1 ORDER BY `name` ASC LIMIT 35 ");
         if($query1 === FALSE) { 
        die(mysqli_error($db)); // TODO: better error handling
                            }
         while ($row = mysqli_fetch_assoc($query1)) {

            $name =$row['name'];
            $id   =$row['id'];

        ?>
    <div class="pop1">


     <a href="quotes.php?auth_id=<?php echo "$id";?>"><?php echo "$name";?></a>


    </div>


    <?php 
    $count++;
    } 
    ?>
    </br>
    <a href='popular_authors.php' class='button'>more popular author</a>

   </div>




  <?php echo pagination($statement,$limit,$page);?> 

  <div style="margin-top:0px"><?php include('footer.php');?></div>

 </body>
 </html>

0 个答案:

没有答案