Question

我是sql的新手，我想从这个表中获取数据：

id       pseudo         amount      date
1        test1          34          2015-09-16 09:21:51
2        test2          78          2015-09-14 09:21:51
3        test3          896         2015-10-01 09:21:51
4        test4          67          2015-11-16 09:21:51
5        test5          12          2015-09-23 09:21:51
6        test6          19          2015-09-09 09:21:51

我想在一个查询中获得最大amount和最后3个lignes按日期排序的ligne ...我可以在2个查询中执行此操作，但我想要此问题的最佳选项。你能帮我吗？对不起我的英文：）

pseudo                amount
test3                 896
test4                 67
test5                 12
test1                 34
test2                 78

Answer 1

根据您的假设数据，我们可以使用 MAX 条件和 CTE

来实现此目的

declare @Table1 TABLE 
    (id int, pseudo varchar(5), amount int, date varchar(19))
;

INSERT INTO @Table1
    (id, pseudo, amount, date)
VALUES
    (1, 'test1', 34, '2015-09-16 09:21:51'),
    (2, 'test2', 78, '2015-09-14 09:21:51'),
    (3, 'test3', 896, '2015-10-01 09:21:51'),
    (4, 'test4', 67, '2015-11-16 09:21:51'),
    (5, 'test5', 12, '2015-09-23 09:21:51'),
    (6, 'test6', 19, '2015-09-09 09:21:51')
;
;WITH CTE AS (
select *,
ROW_NUMBER()OVER(PARTITION BY TN ORDER BY TN) RW 
from (
select id,
    pseudo,
    amount,
    MAX(pseudo)OVER( ORDER BY amount desc )TN from @Table1 )T )
,cte2 as (
Select top 3 pseudo,
amount 
from CTE 
    WHERE RW = 2  order by amount)
Select pseudo,amount from CTE WHERE RW = 1 AND pseudo <> 'test6'
UNION ALL 
select  pseudo,amount from cte2

在sql

1 个答案: