Question

如何在不创建存储过程，日历表或递归函数的情况下列出SQL Server中两个日期参数之间的所有日期？

Answer 1

始终是递归CTE选项：

DECLARE @STARTDATE DATETIME
DECLARE @ENDDATE DATETIME

SET @STARTDATE = '2015-01-01'
SET @ENDDATE = '2015-12-31'

;WITH DATE_RANGE (DATES) AS (
    SELECT DATEADD(DAY, DATEDIFF(DAY, 0, @STARTDATE), 0)
        UNION ALL SELECT DATEADD(DAY, 1, DATES)
            FROM DATE_RANGE
            WHERE DATEADD(DAY, 1, DATES) <= @ENDDATE)
SELECT DATES
FROM DATE_RANGE
OPTION (MAXRECURSION 0)

请务必使用MAXRECURSION选项，否则您的结果将被限制为默认值为100。

Answer 2

这在Master数据库的spt_values表上使用Row_Number来创建日期范围内的年，月和日期列表。然后将其内置到日期时间字段中，并过滤为仅返回输入的日期参数中的日期。

执行非常快，并在不到1秒的时间内返回500年的日期（182987天）。

Declare @DateFrom datetime = '2000-01-01'
declare @DateTo datetime = '2500-12-31'
Select
*
From
    (Select
    CAST(CAST(years.Year AS varchar) + '-' + CAST(Months.Month AS varchar) + '-' + CAST(Days.Day AS varchar) AS DATETIME) as Date

    From
    (select row_number() over(order by number) as Year from master.dbo.spt_values) as Years
    join (select row_number() over(order by number) as Month from master.dbo.spt_values) as Months on 1 = 1
    join (select row_number() over(order by number) as Day from master.dbo.spt_values) as Days on 1 = 1
    Where 
    Years.Year between datepart(year,@DateFrom) and datepart(year,@DateTo)
    and Months.Month between 1 and 12
    and 
    Days.Day between 1 and datepart(day,dateadd(day,-1,dateadd(month,1,(CAST(CAST(Years.Year AS varchar)+'-' + CAST(Months.Month AS varchar) + '-01' AS DATETIME)))))
    ) as Dates
Where Dates.Date between @DateFrom and @DateTo

order by 1

Answer 3

以下将是您的解决方案

import com.datastax.driver.core.Cluster
import com.datastax.driver.core.ProtocolOptions.Compression

val builder: Cluster.Builder = Cluster.builder
builder.addContactPoint(A.address)
builder.addContactPoint(B.address)
builder.addContactPoint(C.address)

val cluster: Cluster = builder.withCompression(Compression.SNAPPY).build

Answer 4

简单的结果。

DECLARE @DATE1 DATE
DECLARE @DATE2 DATE
SET @DATE1 ='20020101'
SET @DATE2 = '20020311'

WHILE(@DATE1<=@DATE2)
Begin
PRINT @DATE1
set @DATE1 = DATEADD(dd,1,@DATE1)
END

如何在SQL中列出两个日期参数之间的所有日期

4 个答案: