这是表格。
!important
我有5000条记录。我想要得到的是以下结果: 有57个相机,它们各有不同,但有3个相同,都是
CREATE TABLE cameras
(
id integer NOT NULL DEFAULT nextval('sq_streams'::regclass),
created_at timestamp with time zone NOT NULL DEFAULT now(),
updated_at timestamp with time zone NOT NULL DEFAULT now(),
exid text NOT NULL,
owner_id integer NOT NULL,
is_public boolean NOT NULL,
config json NOT NULL,
name text NOT NULL,
last_polled_at timestamp with time zone DEFAULT now(),
is_online boolean,
timezone text,
last_online_at timestamp with time zone DEFAULT now(),
location geography(Point,4326),
mac_address macaddr,
model_id integer,
discoverable boolean NOT NULL DEFAULT false,
preview bytea,
thumbnail_url text,
CONSTRAINT pk_streams PRIMARY KEY (id)
)
我想创建一个查询,将结果显示为
'external_http_port', config->> 'external_host', config-> 'snapshots'->> 'jpg'
答案 0 :(得分:1)
这是怎么回事?
SELECT config ->>'external_http_port' AS external_http_port,
config->> 'external_host' AS external_host,
config-> 'snapshots'->> 'jpg' AS snapshots,
count(*)
FROM cameras
GROUP BY config->>'external_http_port', config->> 'external_host', config-> 'snapshots'->> 'jpg'
HAVING count(*) > 1;
答案 1 :(得分:0)
它能解决这个问题吗? (想象一个类比,而不是文字)
double units