我已经给出了下面的数组。我的问题是如何根据日期处理数据。 例如:低于服务的响应。
[[
{"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
]]
我想根据日期处理数据如下:
20/09/2015
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"}
20/10/2015
{"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"}
2015年12月9日
{"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"}
先谢谢。
答案 0 :(得分:1)
为此做一些安排功能。 arrange()返回对象中的分组数据。
array (size=27)
0 => string 'http://php.net' (length=14)
1 => string '
http://php.net/downloads' (length=26)
2 => string '
http://php.net/docs.php' (length=25)
3 => string '
http://php.net/get-involved' (length=29)

答案 1 :(得分:0)
好吧,我会这样想:
我没有提及转换等类型。
答案 2 :(得分:0)
您可以使用.filter
function reduceArr(x, date){
return x[0].filter(function(elem){
return elem.dateAssessed==date;
});
}
console.log(reduceArr(x, "20/09/2015"));
这将返回所需对象的数组。
答案 3 :(得分:0)
不清楚您的问题,但如果您想按日期对其进行分组,则:
var arr=[
{"claimNumber":"6396","itemNumber":"1","dateAssessed":"20/10/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"918","itemNumber":"1","dateAssessed":"12/09/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2206","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2205","itemNumber":"1","dateAssessed":"20/09/2015"},
{"claimNumber":"2208","itemNumber":"1","dateAssessed":"20/09/2015"},
];
var newarr = {};
for(var i=0; i<arr.length;i++){
newarr[arr[i].dateAssessed] = newarr[arr[i].dateAssessed] || [];
newarr[arr[i].dateAssessed].push(arr[i]);
}