Question

运行PDO MySQL查询时出错，无法解决原因

如果我执行以下操作

    $sql = 'SELECT * FROM ' . $table;
    if ($where !== false)
        $sql .= ' WHERE ' . implode(' AND ', $where);
    $sql .= ' LIMIT 0, 1';
    $variables = array('index');

    $this->DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );

    $statement = $this->DBH->prepare($sql);
    $statement->execute($variables);
    $statement->setFetchMode(PDO::FETCH_ASSOC);
    $rows = $statement->fetch()

它工作正常，我得到了预期的结果。但是如果我改变了

    $sql .= ' LIMIT 0, 1';
    $variables = array('index');

要

    $sql .= ' LIMIT ?, ?';
    $variables = array('index', 0, 1);

$ rows返回一个空数组，我发出以下警告;

Warning: PDOStatement::execute(): SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''0', '1'' at line 1 in file.php on line 96("$statement->execute($variables);"

输出的$ sql和$变量是：

SELECT * FROM ma_pages WHERE url = ? LIMIT ?, ? Array ( [0] => index [1] => 0 [2] => 1 )

Answer 1

试试这个：

$sql = 'SELECT * FROM ' . $table;
if ($where !== false)
    $sql .= ' WHERE ' . implode(' AND ', $where);
$sql .= ' LIMIT :skip, :max';
$variables = array('index');

$this->DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );

$statement = $this->DBH->prepare($sql);
$statement->bindValue(':skip', 0, PDO::PARAM_INT);
$statement->bindValue(':max', 1, PDO::PARAM_INT);
$statement->execute();
$statement->setFetchMode(PDO::FETCH_ASSOC);
$rows = $statement->fetch()

Answer 2

你必须像这样使用PDO::PARAM_INT：

$sql .= " LIMIT :start, :end";

$statement->bindParam(':start', $start, PDO::PARAM_INT);
$statement->bindParam(':end', $end, PDO::PARAM_INT);

MySQL PDO限制问题

2 个答案: