Question

我试着解决这个问题两天而且我无法解决我知道为什么代码会发生但我不知道在哪里。
或者为什么会发生......

这必须在PLSQL中完成这是一项家庭作业。

SET SERVEROUTPUT ON
DECLARE

  V_IDNO      PAYDATA1.IDNO%TYPE;
  V_NAME      PAYDATA1.NAME%TYPE;
  V_SAL       PAYDATA1.SALARY%TYPE;
  V_JOB       PAYDATA1.JOBCODE%TYPE;
  V_PAY       PAYDATA1.PAYHR%TYPE;
  V_IDNO1     PAYTRAN1.IDNO%TYPE;
  V_HOURSWK   PAYTRAN1.HOURSWK%TYPE; 
  V_HOURS     HOURSWKD.HOURSWK%TYPE; 

  V_CHECK    NUMBER(10);
CURSOR paydata_cursor IS
     SELECT IDNO, NAME, JOBCODE, SALARY, PAYHR FROM PAYDATA1
     ORDER BY IDNO;
CURSOR paytran_cursor IS
     SELECT IDNO, HOURSWK FROM PAYTRAN1
     WHERE V_IDNO = IDNO
     order by IDNO;
BEGIN
OPEN paydata_cursor;
LOOP
FETCH paydata_cursor INTO V_IDNO, V_NAME, V_CHECK, V_JOB, V_PAY;
EXIT WHEN paydata_cursor%NOTFOUND;

IF V_SAL > 0 THEN
V_CHECK := V_SAL / 52;

DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);

END IF;

IF V_SAL = 0 AND V_HOURSWK < 41 THEN
V_CHECK := V_PAY * V_HOURS;

DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);

ELSIF V_SAL = 0 AND V_HOURSWK > 40 THEN
V_CHECK := V_PAY * V_HOURS;
V_CHECK := V_SAL + ((V_HOURSWK * 1.5) * (V_HOURSWK - 40));

DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);

END IF;

END LOOP;
CLOSE paydata_cursor;
END;
/
SET SERVEROUTPUT OFF

我得到这个错误，试图把它固定一整天，但不能。有什么建议吗？

SQL> @ CURSOR5
DECLARE
*
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: character to number conversion error
ORA-06512: at line 22

Answer 1

问题是您的专栏paydata1.JOBCODE不是数字在此代码FETCH paydata_cursor INTO V_IDNO, V_NAME, V_CHECK, V_JOB, V_PAY;中，您将其分配给V_CHECK，即数字

更改这样的订单：FETCH paydata_cursor INTO V_IDNO, V_NAME, V_JOB, V_CHECK, V_PAY;它应该有效但请确保paydata1.salary是一个数字

此外，我不确定您何时声明V_SAL，然后为什么在此光标提取中使用V_CHECK。

Answer 2

我可以看到您的代码存在一些问题但却不知道更多信息很难诊断......但我会尝试：

打开光标时，您似乎正在选择错误的变量。

您还无法在任何地方打开paytran_cursor。您可以自己添加该代码，但在此之前，您对V_HOURSWK的检查不会非常有用等。

请改为尝试：

SET SERVEROUTPUT ON
DECLARE

  V_IDNO      PAYDATA1.IDNO%TYPE;
  V_NAME      PAYDATA1.NAME%TYPE;
  V_SAL       PAYDATA1.SALARY%TYPE;
  V_JOB       PAYDATA1.JOBCODE%TYPE;
  V_PAY       PAYDATA1.PAYHR%TYPE;
  V_IDNO1     PAYTRAN1.IDNO%TYPE;
  V_HOURSWK   PAYTRAN1.HOURSWK%TYPE; 
  V_HOURS     HOURSWKD.HOURSWK%TYPE; 

  V_CHECK    NUMBER(10);
CURSOR paydata_cursor IS
     SELECT IDNO, NAME, JOBCODE, SALARY, PAYHR 
       FROM PAYDATA1
      ORDER BY IDNO;
CURSOR paytran_cursor IS
     SELECT IDNO, HOURSWK 
       FROM PAYTRAN1
      WHERE V_IDNO = IDNO
      order by IDNO;
BEGIN
  OPEN paydata_cursor;
  LOOP
    -- Changed the variables you were selecting into
    FETCH paydata_cursor INTO V_IDNO, V_NAME, V_JOB, V_SAL, V_PAY;
    EXIT WHEN paydata_cursor%NOTFOUND;

    IF V_SAL > 0 
    THEN
      V_CHECK := V_SAL / 52;

      DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);
    END IF;

    IF V_SAL = 0 AND V_HOURSWK < 41 
    THEN
      V_CHECK := V_PAY * V_HOURS;

      DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);
    ELSIF V_SAL = 0 AND V_HOURSWK > 40 
    THEN
      V_CHECK := V_PAY * V_HOURS;
      V_CHECK := V_SAL + ((V_HOURSWK * 1.5) * (V_HOURSWK - 40));

      DBMS_OUTPUT.PUT_LINE(V_IDNO|| ' HAS A CHECK FOR: '||V_CHECK);
    END IF;

  END LOOP;
  CLOSE paydata_cursor;
END;
/
SET SERVEROUTPUT OFF

希望它有所帮助。

修改

我试图猜测您要对代码执行的操作，并认为下面的内容可能会以某种方式更有效地解决您的问题：

SET SERVEROUTPUT ON DECLARE -- c_max_hours CONSTANT NUMBER := 40; -- -- N.B.: I have assumed that there may be more than one entry per IDNO for -- hours worked, if this is not the case then you can remove the SUM() and -- the GROUP BY clause -- CURSOR pay_cursor IS SELECT IDNO, NAME, JOBCODE, SALARY, PAYHR, SUM(HOURSWK) AS HOURS_WORKED FROM PAYDATA1 JOIN PAYTRAN1 USING (IDNO) GROUP BY IDNO, NAME, JOBCODE, SALARY, PAYHR; -- V_CHECK NUMBER; pay_record pay_cursor%ROWTYPE; -- BEGIN -- Depending on the rows in your cursor you might want to increase the output buffer for DBMS_OUTPUT DBMS_OUTPUT.ENABLE(1000000); -- OPEN pay_cursor; LOOP -- Fetch the data into your cursor rowtype variable FETCH paydata_cursor INTO pay_record; EXIT WHEN pay_cursor%NOTFOUND; -- -- ASSUMPTION: salary is not NULL (i.e. 0 or more). -- IF pay_record.salary > 0 THEN V_CHECK := pay_record.salary / 52; ELSE -- -- Salary must be zero -- IF pay_record.hours_worked <= c_max_hours THEN V_CHECK := pay_record.payhr * pay_record.hours_worked; ELSE -- Must be > c_max_hours V_CHECK := pay_record.payhr * pay_record.hours_worked; V_CHECK := pay_record.salary + ((pay_record.hours_worked * 1.5) * (pay_record.hours_worked - 40)); END IF; END IF; -- -- Output your result -- DBMS_OUTPUT.PUT_LINE(pay_record.idno|| ' HAS A CHECK FOR: '||V_CHECK); END LOOP; CLOSE paydata_cursor; EXCEPTION WHEN others THEN -- Close the cursor if it is still open IF pay_cursor%ISOPEN THEN CLOSE pay_cursor; END IF; -- Re-raise the error RAISE; END; / SET SERVEROUTPUT OFF

我希望它有用。附：我无法在真实的环境中检查这一点，因为我不在我平常的PC上，因此对任何语法错误表示道歉。

Answer 3

当你将光标paydata_cursor定义为像

这样的列时，在第13行

从PAYDATA1中选择IDNO，NAME，JOBCODE，SALARY，PAYHR 由IDNO订购; 列序列IDNO，NAME，JOBCODE，SALARY，PAYHR

但在第23行，即

FETCH paydata_cursor INTO V_IDNO，V_NAME，V_CHECK，V_JOB，V_PAY; 你实际上正在提取像这样的列

IDNO，NAME，JOBCODE，SALARY，PAYHR进入 V_IDNO，V_NAME，V_CHECK，V_JOB，V_PAY

这意味着JOBCODE将进入V_CHECK 和SALARY进入V_JOB
因为薪水必须是数字，而v_check必须是varchar

我认为这就是你收到此错误的原因

由于 SID

错误ORA-06502：PL / SQL：数字或值错误：字符到数字转换错误ORA-06512：在第22行

3 个答案: