Question

我想从表affiliation的数据库列setting_name中列出author_settings 而不重复。这是我的DB：

author_id | setting_name | setting_value
     1       affiliation   King College
     1       biography     Oncology Department
     2       affiliation   Queen Hospital
     2       biography     National Research Center
     3       affiliation   King College

然后，在列表之后，我想根据表author_id中的authors进行设置：

author_id | author_name 
   1           Mary
   2           Hasan
   3           Dexter

首先，我想要所有联盟列表如下：

<affID> 1 </affID>
<affName> King College </affName>

<affID> 2 </affID>
<affName> Queen Hospital </affName>

<affID> 3 </affID>
<affName> National Research Center </affName>

然后对作者来说，联盟将按照这样的作者分配：

<authorID> 1 </authorID>
<name> Mary </name>
<affilitationID> 1 </affiliationID>

 <authorID> 2 </authorID>
    <name> Hasan </name>
    <affilitationID> 2 </affiliationID>

<authorID> 3 </authorID>
<name> Dexter </name>
<affiliationID> 1 </affiliationID>

这是我列出联盟的代码：

$affl=mysqli_query($con,"SELECT DISTINCT author_settings.setting_value, author_settings.setting_name,
                         authors.article_id
                         FROM author_settings
                         INNER JOIN authors ON authors.author_id=author_settings.author_id
                         HAVING author_settings.setting_name='affiliation'")
                         or die(mysql_error());

$affid=1;
while($affl2=mysqli_fetch_array($affl))
{
    $xml.='<affID>'.$affid.'</affID>';
    $xml.='<affName>'.affl2['setting_value'].'</affName>

    $affid++;
}
echo $xml;

我尝试使用SELECT DISTINCT列出没有重复的联盟，但对于第二部分，我不知道如何将其分配给作者。请帮忙。谢谢:)）

Answer 1

解决此问题的一种方法是创建一个包含联属值及其索引的临时表。为此，查询将是：

DROP TABLE IF EXISTS affiliations;

CREATE temporary TABLE affiliations (
  aff_id int(11) NOT NULL AUTO_INCREMENT,
  aff_name VARCHAR(45),
  PRIMARY KEY (aff_id) 
) ;

INSERT INTO affiliations (aff_name) SELECT DISTINCT setting_value FROM author_settings WHERE setting_name='affiliation';

-- Provide results for the list of affiliations
SELECT * FROM affiliations;

-- Provide results for the list of author, with affiliation index
SELECT auth_a.author_id, auth_a.author_name, aff_id
FROM authors AS auth_a JOIN author_settings AS auth_s ON auth_a.author_id = auth_s.author_id AND auth_s.setting_name = 'affiliation' 
JOIN affiliations AS aff ON auth_s.setting_value = aff.aff_name;

如何将数组列表分配给特定数据？

1 个答案: