答案 0 :(得分:3)
也许这个?
gsub
答案 1 :(得分:1)
我最近在C#中回答了有关位移和整数打包的问题。
可能是在这种情况下编写的助手类对你来说是有用的
public static class BinaryConverter
{
public static BitArray ToBinary(this int numeral)
{
return new BitArray(new[] { numeral });
}
public static int ToNumeral(this BitArray binary)
{
if (binary == null)
throw new ArgumentNullException("binary");
if (binary.Length > 32)
throw new ArgumentException("must be at most 32 bits long");
var result = new int[1];
binary.CopyTo(result, 0);
return result[0];
}
public static BitArray Take (this BitArray current, int length )
{
if (current.Length < length)
throw new Exception("Invalid length parameter");
List<bool> taken = new List<bool>();
for (int i = 0; i < length; i++)
taken.Add(current.Get(i));
return new BitArray(taken.ToArray());
}
public static BitArray Shift (this BitArray current, int length )
{
if (current.Length < length)
throw new Exception("Invalid length parameter");
List<bool> shifted = new List<bool>();
for (int i = 0; i < current.Length - length; i++)
shifted.Add(current.Get(length + i));
return new BitArray(shifted.ToArray());
}
public static BitArray FitSize (this BitArray current, int size)
{
List<bool> bools = new List<bool>() ;
bools = bools.InitBoolArray(size);
for (int i = 0; i < current.Count; i++)
bools[i] = current.Get(i) ;
return new BitArray(bools.ToArray());
}
public static List<bool> InitBoolArray(this List<bool> current, int size)
{
List<bool> bools = new List<bool> ();
for (int i = 0; i < size; i++)
bools.Add(false);
return bools ;
}
这里是对该答案的引用 Dynamic Bit Shifting / Unshifting
在上面的链接中显示了如何在同一个整数上包装小数字,你的五个字节非常接近那个问题