Question

给出一系列时间：

["01:08", "03:46", "03:24", "05:53", "01:45", "03:32", "05:19", "08:56", "01:49", "05:40", "05:21", "02:40", "04:26", "02:02", "04:42", "03:58", "02:06", "02:46", "05:21", "03:37", "02:55", "03:26", "04:16", "01:32", "01:42", "03:22", "01:55", "01:41", "05:10", "00:45", "03:23", "05:08", "02:22", "02:34", "02:49", "01:18", "02:13", "01:37", "03:36", "05:26", "05:00", "02:41", "03:08", "01:00", "02:19", "02:33", "03:43", "01:35", "02:59", "01:38", "04:05", "04:15", "03:43", "03:43", "00:25"]

每次都是分钟和秒的持续时间。

如何将这些持续时间加在一起以获得最终持续时间？

我尝试使用日期对象，但我似乎无法弄明白。

Answer 1

对于更实用的样式，您可以使用map将每次转换为秒格式，然后使用reduce获取所有时间的总和。

function toSeconds(time) {
  var minutes = Number(time.slice(0, 2));
  var seconds = Number(time.slice(3));
  return seconds + minutes * 60;
}

function sum(a, b) {
  return a + b;
}

// Assuming your array is named 'arr'
var totalSeconds = arr.map(toSeconds).reduce(sum);
console.log(totalSeconds);

Answer 2

还有一个：

var t = ["01:08", "03:46", "03:24", "05:53", "01:45", "03:32", "05:19", "08:56", "01:49", "05:40", "05:21", "02:40", "04:26", "02:02", "04:42", "03:58", "02:06", "02:46", "05:21", "03:37", "02:55", "03:26", "04:16", "01:32", "01:42", "03:22", "01:55", "01:41", "05:10", "00:45", "03:23", "05:08", "02:22", "02:34", "02:49", "01:18", "02:13", "01:37", "03:36", "05:26", "05:00", "02:41", "03:08", "01:00", "02:19", "02:33", "03:43", "01:35", "02:59", "01:38", "04:05", "04:15", "03:43", "03:43", "00:25"];

var seconds = t.map(function(v) {
                      var ary = v.split(':');
                      return +ary[0] + ary[1] / 60;
              }).reduce(function(p, c) {
                          return p + c;
              });

Answer 3

循环遍历数组时，保持一个总计秒（seconds + (minutes * 60)）。最后从秒转换为MM:SS格式。

var data = ["01:08", "03:46", "03:24", "05:53", "01:45", "03:32", "05:19", "08:56", "01:49", "05:40", "05:21", "02:40", "04:26", "02:02", "04:42", "03:58", "02:06", "02:46", "05:21", "03:37", "02:55", "03:26", "04:16", "01:32", "01:42", "03:22", "01:55", "01:41", "05:10", "00:45", "03:23", "05:08", "02:22", "02:34", "02:49", "01:18", "02:13", "01:37", "03:36", "05:26", "05:00", "02:41", "03:08", "01:00", "02:19", "02:33", "03:43", "01:35", "02:59", "01:38", "04:05", "04:15", "03:43", "03:43", "00:25"];

var durationSum = function(data) {
    var totalSeconds = 0;

    for (var i = 0; i < data.length; i++) {
        var split = data.split(':');
        var minutes = parseInt(split[0]);
        var seconds = parseInt(split[1]);

        totalSeconds = seconds + (minutes * 60);
    }

    var minutes = Math.floor(totalSeconds / 60);
    var seconds = totalSeconds - minutes;

    minutes = minutes.toString();
    seconds = seconds.toString();
    while (minutes.length < 2) minutes = '0' + minutes;
    while (seconds.length < 2) seconds = '0' + seconds;

    return minutes + ':' + seconds;
}

console.log(durationSum(data));

Answer 4

var da = ["01:08", "03:46", "03:24", "05:53", "01:45", "03:32", "05:19", "08:56", "01:49", "05:40", "05:21", "02:40", "04:26", "02:02", "04:42", "03:58", "02:06", "02:46", "05:21", "03:37", "02:55", "03:26", "04:16", "01:32", "01:42", "03:22", "01:55", "01:41", "05:10", "00:45", "03:23", "05:08", "02:22", "02:34", "02:49", "01:18", "02:13", "01:37", "03:36", "05:26", "05:00", "02:41", "03:08", "01:00", "02:19", "02:33", "03:43", "01:35", "02:59", "01:38", "04:05", "04:15", "03:43", "03:43", "00:25"];

var mins = 0;
var secs = 0;

for(var i=0; i<da.length; i++) {
  mins = mins + Number(da[i].substr(0, 2));
  secs = secs + Number(da[i].substr(3, 2));
}

mins = mins + Math.floor(secs / 60);
secs = secs % 60;

console.log(mins + ":" + secs);

Answer 5

将每个条目拆分为分钟和秒，并计算十进制分钟数。添加它们，然后转换回分钟和秒钟。

这里有一个小实用功能来总结一个数组：

Eq a => a -> [a] -> Int

编写另一个小函数来分割时间条目并返回十进制小数分钟。我们将在function add(a, b) { return a + b; } function sum(a) { return a.reduce(add); }下面使用此功能：

map

使用sum函数将使用function split(x) { var parts = elt.split(':'); return +parts[0] + parts[1]/60; }将输入数组的每个元素映射到十进制分钟数的结果总和：

split

现在您可以打印出结果的分钟数和秒数：

var minutes = sum(array.map(split));

Answer 6

这个可爱的小代码是什么？

function sumUp(x){
  var min = 0;
  [].forEach.call(x, function(inst){
    var _x = inst.split(":");
    min += +(_x[0])*60 + +(_x[1]);
  });
  return Math.floor(min/60)+":"+(min%60);
}

此处x是一个时间数组。

在Javascript中一起添加持续时间

6 个答案: