Question

Hellos在这里有点受阻我想要一个有限的弦乐例如：只有前两个值db_id 1和2

 {

    date = "12/01/2012";
    "db_id" = 1;
},
    {

    date = "10/01/2012";
    "db_id" = 2;

},
    {

    date = "09/12/2015";
    "db_id" = 3;

},
    {

    date = "10/12/2015";
    "db_id" = 4;

},



  NSString *requestString = @"url";
  NSData *data = [NSData dataWithContentsOfURL:[NSURL URLWithString:requestString]];
    NSError *error;
    NSDictionary *JSON = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
    NSArray *Array = [JSON valueForKey:@"moods"];
    NSLog(@"%@",Array);


for (NSMutableArray *result in Array)

{

    NSDictionary* Date = [result valueForKey:@"db_id"];
    NSLog(@"%@",Date );



}

这是我的控制台在这种情况下我有10个字符串，但我只对前5个感兴趣

2015-12-17 10:34:21.978 App[5673:1609864] 1
2015-12-17 10:34:21.978 App[5673:1609864] 2
2015-12-17 10:34:21.978 App[5673:1609864] 3
2015-12-17 10:34:21.978 App[5673:1609864] 4
2015-12-17 10:34:21.979 App[5673:1609864] 5
2015-12-17 10:34:21.979 App[5673:1609864] 6
2015-12-17 10:34:21.979 App[5673:1609864] 7
2015-12-17 10:34:21.979 App[5673:1609864] 8
2015-12-17 10:34:21.980 App[5673:1609864] 9
2015-12-17 10:34:21.980 App[5673:1609864] 10

Answer 1

NSMutableArray *result;
for (int i = 0 ; i < Array.count ; i++)
{

    NSDictionary* Date = [result valueForKey:@"db_id"];
    NSLog(@"%@",Date );

}

iOS Json获取前两个字符串的确定数量

1 个答案: