如何让Yii2处理数据提供者的两个不同实例?

时间:2015-12-17 05:24:59

标签: php widget yii2 dataprovider

这是siteController index.php。 在这里,我想在同一页面上显示来自不同表的两个列表。但是它只显示两个div的一个表数据。当我在两个div小部件上只设置$ dataProvider时如果我设置$ dataProvider2在actionIndex()中创建它会得到错误找不到$ dataProvider2。

                        <?= GridView::widget([
                        'dataProvider' => $dataProvider,
                        'columns' => [
                            ['class' => 'yii\grid\SerialColumn'],
                       [

                           'attribute'=>'practiceCode',
                           'format' => 'raw',
                           'value'=>function ($model, $index, $widget) {
                       },
                    ],
                    'firstName',

                        ],

              ]); ?>

            </div>
            <div class="col-lg-6" style="border:solid 1px;">
                <h2>Member</h2>
                <?= GridView::widget([
                        'dataProvider2' => $dataProvider2,//Error $dataProvider2 not found
                        'columns' => [
                            ['class' => 'yii\grid\SerialColumn'],
                       [

                           'attribute'=>'memberCode',
                           'format' => 'raw',
                           'value'=>function ($model, $index, $widget) {

                       },
                    ],
                    'firstName',
              ]); ?>    
            </div>

这是actionIndex()这里我写了两个dataProvider($ dataProvider,$ dataProvider2)但我无法在index.php小部件中设置此dataProvider

public function actionIndex()
    {
        $query = new \yii\db\Query;
        $query->select('*')
              ->from('practice');
        $query->createCommand();

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
            'pagination' => [
            'pageSize' => 10,
             ],
        ]);
        $query = new \yii\db\Query;
        $query->select('*')
              ->from('member');
        $query->createCommand();

        $dataProvider2 = new ActiveDataProvider([
            'query' => $query,
            'pagination' => [
            'pageSize' => 10,
             ],
]);
        return $this->render('index', [
            'dataProvider' => $dataProvider,'dataprovider2'=>$dataProvider2 ]);
}

1 个答案:

答案 0 :(得分:6)

您需要将dataProvider2更改为dataProvider

<div class="col-lg-6" style="border:solid 1px;">
<h2>Member</h2>
<?= GridView::widget([
    'dataProvider' => $dataProvider2,//Error $dataProvider2 not found
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        [

            'attribute'=>'memberCode',
            'format' => 'raw',
            'value'=>function ($model, $index, $widget) {

            },
        ],
        'firstName',
    ]
]); ?>

由于dataProvider是GridView的属性..它将起作用

将控制器操作更改为

return $this->render('index', [
        'dataProvider' => $dataProvider,'dataProvider2'=>$dataProvider2 ]);