Question

我有一个计算器应用程序，我想根据用户长时间触摸的计算器按钮显示不同的警报视图文本。我有很长的触摸代码。如何确定长触摸发生在哪个计算器按钮上？

-(void)handleLongTapGesture:(UITapGestureRecognizer *)sender{

    if (sender.state == UIGestureRecognizerStateEnded) {
    }
    else if (sender.state == UIGestureRecognizerStateBegan){

    // The alert view text should change, depending on which calculator button is long touched
        UIAlertView *alert = [[UIAlertView alloc]initWithTitle: @"I want the alert view text to change according to what calculator button is long touched"
                                                       message: @""
                                                      delegate: self
                                             cancelButtonTitle:nil
                                             otherButtonTitles:@"OK", nil]; 


        [alert setTag:1];
        [alert show];

      }
}

// This code only produces a set of X-Y coordinates if the User touches between calculator buttons, not on the button itself
-(void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    UITouch *touch = [[event allTouches] anyObject];
    CGPoint location = [touch locationInView:touch.view];
    NSLog(@"location.x = %f", location.x);
    NSLog(@"location.y = %f", location.y);
}

Answer 1

两个选项：

为每个视图创建一个手势识别器，您需要检测手势，所有这些都使用相同的目标。然后，您只需使用识别器的view属性即可找到手势发生的视图（或按钮）。
创建单个手势识别器（在要检测手势的视图/按钮的超级视图上），然后使用locationInView:查找手势的位置，并hitTest:withEvent:到找到具体的子视图。

iOS确定在imageview中发生哪个按钮长按

1 个答案: