Question

标题很乱，看到代码

可能要快得多

p1_dado = rand() % 6 + 1;

        switch (p1_dado) {
        case 1:
            cout << ".-----." << endl;
            cout << "|     |" << endl;
            cout << "|  o  |" << endl;
            cout << "|     |" << endl;
            cout << "._____." << endl << endl;
            p1_somma = p1_somma + p1_dado;
            break;
        case 2:
            cout << ".-----." << endl;
            cout << "| o   |" << endl;
            cout << "|     |" << endl;
            cout << "|   o |" << endl;
            cout << "._____." << endl << endl;
            p1_ndadi--;
            break;
        case 3:
            cout << ".-----." << endl;
            cout << "|o    |" << endl;
            cout << "|  o  |" << endl;
            cout << "|    o|" << endl;
            cout << "._____." << endl << endl;
            p1_somma = p1_somma + p1_dado;
            break;
        case 4:
            cout << ".-----." << endl;
            cout << "| o o |" << endl;
            cout << "|     |" << endl;
            cout << "| o o |" << endl;
            cout << "._____." << endl << endl;
            p1_somma = p1_somma + p1_dado;
            break;
        case 5:
            cout << ".-----." << endl;
            cout << "| o o |" << endl;
            cout << "|  o  |" << endl;
            cout << "| o o |" << endl;
            cout << "._____." << endl << endl;
            p1_ndadi--;
            break;
        case 6:
            cout << ".-----." << endl;
            cout << "| o o |" << endl;
            cout << "| o o |" << endl;
            cout << "| o o |" << endl;
            cout << "._____." << endl << endl;
            p1_somma = p1_somma + p1_dado;
            break;
        }

我还应该提一下，这段代码在for循环中，因此switch case将运行4-5次。这个输出的方式是彼此重叠的所有骰子，有没有办法在1＆＃34;行＆＃34;中显示所有骰子。？像：

1 2 3 4 5

而不是：

感谢您的帮助：）

Answer 1

假设您安装了拦截和重新排列输出的东西，实际输出可以保持不变。由于我倾向于将流编译行的密钥发送到流的刷新，因此唯一真正需要的更改是使用'\n'替换excessive use of std::endl。这是我强烈推荐的东西（有关解释，请查看link）。

因此，假设有一个名为dicebuf的东西被定义，main()函数可能看起来像这样（有趣的部分是函数内的第一个定义）：

int main()
{
    dicebuf buf(std::cout);

    for (int i = 0; i != 5; ++i)
    {
        int p1_dado = rand() % 6 + 1;
        switch (p1_dado) {
        case 1:
            std::cout << ".-----." << '\n';
            std::cout << "|     |" << '\n';
            std::cout << "|  o  |" << '\n';
            std::cout << "|     |" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        case 2:
            std::cout << ".-----." << '\n';
            std::cout << "| o   |" << '\n';
            std::cout << "|     |" << '\n';
            std::cout << "|   o |" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        case 3:
            std::cout << ".-----." << '\n';
            std::cout << "|o    |" << '\n';
            std::cout << "|  o  |" << '\n';
            std::cout << "|    o|" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        case 4:
            std::cout << ".-----." << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "|     |" << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        case 5:
            std::cout << ".-----." << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "|  o  |" << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        case 6:
            std::cout << ".-----." << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "| o o |" << '\n';
            std::cout << "._____." << '\n' << '\n';
            break;
        }
    }
}

这里的想法是dicebuf构造函数注入一个聚合行的自定义流缓冲区。它根本不输出东西，只是将字符添加到当前行。如果遇到换行符（'\n'），则会转到下一行。如果遇到连续的两个换行符，则会假定有时间返回到顶部并继续添加到当前行。

通过实现合适的流缓冲区（即，从std::streambuf派生的类）来创建拦截输出的这种实用程序。以下是一个示例实现：

#include <utility>
#include <iostream>
#include <iterator>
#include <algorithm>
#include <string>
#include <vector>

struct dicebuf
    : std::streambuf
{
    std::ostream&                       out;
    std::streambuf*                     sbuf;
    std::vector<std::string>            rows;
    std::vector<std::string>::size_type row;
public:
    dicebuf(std::ostream& out)
        : out(out)
        , sbuf(out.rdbuf())
        , rows(1)
        , row(0) {
        out.rdbuf(this);
    }
    ~dicebuf() {
        this->sync();
        this->out.rdbuf(this->sbuf);
    }
    int overflow(int c) {
        if (c != std::char_traits<char>::eof()) {
            if (c == '\n') {
                if (this->rows[this->row].empty()) {
                    this->row = 0;
                }
                else {
                    ++this->row;
                    if (this->rows.size() == this->row) {
                        this->rows.push_back(std::string());
                    }
                }
            }
            else {
                this->rows[this->row].push_back(c);
            }

        }
        return std::char_traits<char>::not_eof(c);
    }
    int sync() {
        std::ostream out(this->sbuf);
        std::copy(this->rows.begin(), this->rows.end(),
                  std::ostream_iterator<std::string>(out, "\n"));
        this->sbuf->pubsync();
        this->row = 0;
        this->rows.resize(0);
        this->rows.push_back(std::string());
        return 0;
    }
};

与上面的main()一起，它应该根据需要产生输出。如果您想要多行显示结果，您只需注入一个刷新，例如，使用

std::flush;

在战略要点。

Answer 2

代码段：

char* hline = ".-----.";
char* dice[6][3] = { {"|     |", "|  o  |", "|     |" }, { ... }}; // 3 middle lines for each dice

for (int l=0; l < 5; ++l) {
  for(int i=0; i < 6; ++i) // or any random dice sequence with index = dice value - 1
    cout << (l == 0 || l == 4) ? hline : dice[i][l-1] << " ";
  cout << "\n";
}

使std :: cout一个接一个地输出同一行中的多个字符串

2 个答案: