Question

我正在尝试用C ++制作我的第一个文本到游戏。唯一的问题是我的代码中的默认语句使游戏出现故障。我正在尝试使用另一个名为exceptionHandler的函数来处理默认语句，但它似乎并没有起作用。有什么建议？这是代码：

#include <iostream>
#include <cstdlib>

using namespace std;

void space(), menu(), exceptionHandler();
int back1, back2;

int main()
{
   cout << "Siddiqui Interactive presents..." << endl;
   cin.get();
   system("CLS");
   cout << "Outland" <<endl;
   cin.get();
   int bob = 0;
   //to loop back to main menu
   while(bob < 5){
     system("CLS");
     cout << "Outland" <<endl;
     space();
     cout << "Press 1 to begin" <<endl;
     cout << "Press 2 for credits" <<endl;
     cout << "Press 3 to quit" <<endl;
     int switch1;
     cin >> switch1;
     switch(switch1){
         case 1:
             //nothing here for now
             break;
         case 2:
            system("CLS");
            menu();
            if(back1 == 1){
                   system("CLS");
                   //clears screen to loop back to the menu
             }
             break;
         case 3:
            return 0;
            break;
        default:
            system("CLS");
            exceptionHandler();
       }
  }
  return 0;
}

void menu(){
   //to create a function for the menu, saves time
   cout << "This game was coded by: Shahmir Siddiqui and Ibrahim" <<endl;
   cout << "Outland was designed by: Azmir Siddiqui" <<endl;
   space();
   cout << "Press 1 to go back" <<endl;
   cin >> back1;
}

void space(){
   //just saves time
   cout << "" <<endl;
}

void exceptionHandler(){
    //to handle exceptions or errors
    system("CLS");
    cout << "Invalid!" <<endl;
    space();
    cout << "Press 1 to go back" <<endl;
    cin >> back2;
    if(back2 == 1){
       system("CLS");
       //also clears screen to loop back to main menu
    }
}

编辑：让我们说，我输入的是d而不是1，它只是在错误屏幕和主菜单之间继续波动。

Answer 1

cin >> switch1尝试读取整数。如果您输入d（无法将其转换为int，则不会输入错误输入，因此您必须手动清除它。< / p>

尝试将此添加到您的错误案例中：

cin.clear();
cin.ignore(INT_MAX, '\n');

在while循环中使用switch语句时，C ++会继续出现故障

1 个答案: