Question

我想使用输入类型'file'作为多个添加图像goa.jpg，kerala.jpg，delhi.jpg。以下代码完美地插入单个图像。

现在我想使用for循环执行多个图像上传，但我没有得到没有错误的实际代码。任何人都有这方面的经验吗？

                $file_name=$_FILES["packageimage"]["name"];
                $temp_name=$_FILES["packageimage"]["tmp_name"];
                $imgtype=$_FILES["packageimage"]["type"];   if($imgtype!='image/jpeg'&&$imgtype!='image/jpg'&&$imgtype!='image/gif'&&$imgtype!='image/png'&&$imgtype!='image/bmp')
        {     $msg = "Please upload only Image file";   }
         else{ 
        $ext= GetImageExtension($imgtype);
                $imagename=date("d-m-Y")."--".time().$ext;
                $target_path = "../upload/products/".$imagename;
                move_uploaded_file($temp_name, $target_path);

// query to insert images.

        $query=mysql_query("insert into tbl_products set catid='".$catid."', packageimage='".$imagename."',  add_date=now()");
        if($query)
        {
        $msg="Product Added Successfull";
        }

当我在上面的代码中尝试使用for循环时，它只存储第一个图像并仅显示第一个图像。

Answer 1

请看看你可以了解多重上传的所有想法 http://php.net/manual/en/features.file-upload.multiple.php

见下文示例

searchReleases($("[name=release]").val());


function searchReleases(givenName) {
    var list;
    var data = givenName;
    @foreach (var a in @Model.Releases) {
        if (@a.Name.Contains(givenName)) {
           list+= a.Name + "=";
        }
    }
}

参见结果如下

<?php 
print_r($_FILES);
?>
<form action="" method="post" enctype="multipart/form-data">
  Send these files:<br />
  <input name="userfile[]" type="file" /><br />
  <input name="userfile[]" type="file" /><br />
  <input type="submit" value="Send files" />
</form>

以下是foreach的问题

Array
(
    [userfile] => Array
        (
            [name] => Array
                (
                    [0] => cancelled booking - PAYG.png
                    [1] => cancelled booking - PAYG.png
                )

            [type] => Array
                (
                    [0] => image/png
                    [1] => image/png
                )

            [tmp_name] => Array
                (
                    [0] => C:\xampp\tmp\php402A.tmp
                    [1] => C:\xampp\tmp\php402B.tmp
                )

            [error] => Array
                (
                    [0] => 0
                    [1] => 0
                )

            [size] => Array
                (
                    [0] => 99134
                    [1] => 99134
                )

        )

)

当结果看到Bellow：

<?php 
foreach ($_FILES['userfile'] as $position => $file){
    print_r($file);

}

?>

所以现在你可以理解了

由于 PRATIK

Answer 2

您可以使用multiple属性上传多个文件，如下所示：

<强> HTML

<form action="upload.php" method="post" enctype="multipart/form-data">
  <input type="file" multiple="multiple" name="packageimage[]" />
  <input type="submit" value="Upload" name="submit" />
</form>

<强> PHP

<?php

    if(isset($_POST['submit'])){
        // directory where the files will get uploaded
        $target_dir = "upload" . DIRECTORY_SEPARATOR . "products";

        // count the number of files uploaded
        $num_of_files = count($_FILES["packageimage"]["name"]);

        // loop through each file to upload
        for($i = 0; $i < $num_of_files; ++$i){

            // valid file extensions
            $valid_extensions = array("gif", "png", "jpg", "jpeg", "bmp");

            // get the file extension
            $ext = strtolower(pathinfo($_FILES["packageimage"]["name"][$i],PATHINFO_EXTENSION));

            // now check against permissible extensions
            if(in_array($ext, $valid_extensions)){

                // target file name
                $target_file = $target_dir . DIRECTORY_SEPARATOR . date("d-m-Y") . "--" . time() . "." . $ext;

                // upload file
                if (move_uploaded_file($_FILES["packageimage"]["tmp_name"][$i], $target_file)) {
                    echo "The file ". basename($_FILES["packageimage"]["name"][$i]). " has been uploaded. <br />";

                    // do your database operations here

                } else {
                    echo "Sorry, there was an error uploading your file.";
                }
            }else{
                echo "Please upload only Image file";
            }

        }
    }

?>

旁注：为了提供跨平台兼容性，您应该使用PHP的DIRECTORY_SEPARATOR常量来编写路径字符串，例如： "..".DIRECTORY_SEPARATOR."foo"，因为在Windows上执行此操作的方式为"..\foo"，而在其他所有内容（Linux，UNIX，Mac OS X）上，它将为"../foo"。

如何在PHP中执行多个图像插入和上传？

2 个答案: