json响应表

Question

我有一个json响应，我在下面显示使用li并且我将数据保存为doc by data（doc1）的一部分但是当我去表而不是list时我无法保存元素详细信息数据（doc1）.help需要请

JSON RESPONSE
{
   "Envelope":{
      "Body":{
         "processResponse":{
            "NameList":[
               {
                  "EmpId":"1036",
                  "Name":"A Gopalan",
                  "PersonId":"29983"
               },
               {
                  "EmpId":"1904",
                  "Name":"Raghavan, Mr. Gopal",
                  "PersonId":"28795"
               }
            ],
            "client":"http:\/\/xmlns.oracle.com\/InternetMobile\/AbsManagement\/BPELProcessContact",
            "xmlns":"http:\/\/xmlns.oracle.com\/InternetMobile\/AbsManagement\/BPELProcessContact"
         }
      },

if(result.responseJSON.Envelope.Body.processResponse.NameList.length>0)
 	 displayfeed1(result.responseJSON.Envelope.Body.processResponse.NameList);
function displayfeed1(result)
 {
 	var ul="";
 	var li="";
 	
 	jQuery('#show1').remove();
 	        ul = $('#mydemo1');
 	        ul.html(null);
            for (var i = 0; i <= result.length; i++) 
            {
         	   
         	   var doc1 = result[i];
         	   
         	 li = $('<li/>').html(doc1.Name).data(doc1);
         	 li.append($('<br/>'));
             
              li.append($('<hr>'));
              ul.append(li);
        
            }
 }

<ul id="mydemo1" style="text-align:left;"> </ul>