在我的项目中,我从Android设备发送数据,并使用php脚本将其插入数据库。但是相同的数据被插入两次。 (please see here) 我的代码出了什么问题?
机器人:
try {
String data=URLEncoder.encode("name", "UTF-8")+"="+URLEncoder.encode(Name, "UTF-8");
data+="&"+URLEncoder.encode("family", "UTF-8")+"="+URLEncoder.encode(Family, "UTF-8");
data+="&"+URLEncoder.encode("city", "UTF-8")+"="+URLEncoder.encode(City, "UTF-8");
data+="&"+URLEncoder.encode("ostan", "UTF-8")+"="+URLEncoder.encode(Ostan, "UTF-8");
data+="&"+URLEncoder.encode("tel", "UTF-8")+"="+URLEncoder.encode(Tel, "UTF-8");
data+="&"+URLEncoder.encode("sef", "UTF-8")+"="+URLEncoder.encode(sef1, "UTF-8");
data+="&"+URLEncoder.encode("bod", "UTF-8")+"="+URLEncoder.encode(bodjeh1, "UTF-8");
data+="&"+URLEncoder.encode("tab", "UTF-8")+"="+URLEncoder.encode(tabgh, "UTF-8");
data+="&"+URLEncoder.encode("img", "UTF-8")+"="+URLEncoder.encode(imgs, "UTF-8");
data+="&"+URLEncoder.encode("imgf", "UTF-8")+"="+URLEncoder.encode(fimage, "UTF-8");
URL link=new URL(MainActivity.url+"/app/order.php");
URLConnection con=link.openConnection();
con.setDoOutput(true);
OutputStreamWriter wrw=new OutputStreamWriter(con.getOutputStream());
wrw.write(data);
wrw.flush();
BufferedReader br=new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBuilder sb=new StringBuilder();
String l="";
while((l=br.readLine())!=null){
sb.append(l);
}
r=sb.toString();
br.close();
插入代码 - php
$name=$_POST['name'];
$family_name=$_POST['family'];
$city=$_POST['city'];
$ostan=$_POST['ostan'];
$tel=$_POST['tel'];
$comment=$_POST['sef'];
$bod=$_POST['bod'];
$tab=$_POST['tab'];
$img=$_POST['img'];
$imgf=$_POST['imgf'];
$sql="INSERT INTO `customer_table`(`id`, `name`, `family_name`, `city`, `ostan`, `tel`, `comment`,`bodjeh`,`tabagheh`,`imag_f`,`image`)
VALUES ('','$name','$family_name','$city','$ostan','$tel','$comment','$bod','$tab','$imgf','$img')";
答案 0 :(得分:1)
请使用以下方法将数据发送到服务器
首先将您的请求json转换为简单的地图,如
private JSONObject sendRequest(String urlString, Map<String, String> map, String fileKey, File file) {
StringBuilder strData= null;
JSONObject resObj = null;
try {
Log.i("Send request", urlString+"="+map);
URL url = new URL(urlString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(50000);
conn.setConnectTimeout(50000);
conn.setRequestMethod("POST");
conn.setUseCaches(false);
conn.setDoInput(true);
conn.setDoOutput(true);
if(map == null)
{
map = new HashMap<>();
}
MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
for (HashMap.Entry<String, String> entry : map.entrySet()) {
String k = entry.getKey();
String v = entry.getValue();
reqEntity.addPart(k, new StringBody(v));
}
if(file != null && !TextUtils.isEmpty(fileKey))
{
FileBody filebody = new FileBody(file, "image/*");
reqEntity.addPart(fileKey, filebody);
}
conn.setRequestProperty("Connection", "Keep-Alive");
conn.addRequestProperty("Content-length", reqEntity.getContentLength() + "");
conn.addRequestProperty(reqEntity.getContentType().getName(), reqEntity.getContentType().getValue());
OutputStream os = conn.getOutputStream();
reqEntity.writeTo(os);
os.close();
conn.connect();
if (conn.getResponseCode() == HttpURLConnection.HTTP_OK) {
BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String sResponse;
strData = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
strData = strData.append(sResponse);
}
}
if(strData != null)
resObj = new JSONObject(strData.toString());
} catch (Exception e) {
e.printStackTrace();
}
return resObj;
}
然后使用以下方法调用Webservice。
$result = mysql_query($sql);
if(count($result) > 0)
{
echo "1";
}else
{
echo "0";
}
你需要做的PHP代码:
render()