Question

我有以下JSON我从我的数据库发回，我正在尝试访问＆＃39;名称＆＃39;和＆＃39;联系人的密钥：

[
  {
    "key": {
      "name": "a",
      "kind": "Users",
      "path": [
        "Users",
        "a"
      ]
    },
    "data": {
      "fullname": "a",
      "password": "a",
      "contacts": [
        "bob", "john"
      ]
    }
  },
  {
    "key": {
      "name": "b",
      "kind": "Users",
      "path": [
        "Users",
        "b"
      ]
    },
    "data": {
      "fullname": "b",
      "password": "b",
      "contacts": [
        "john"
      ]
    }
  }
]

我的java脚本回调函数看起来像这样，在里面我试图打印来自实体变量的值：

dataset.get(keys, function(err, entities) {});

我试过：entities.key.name[0]获取名字的第一个键值，但它不起作用。我也被困在如何获取联系人变量。

Answer 1

使用控制台查看内容：

var entities = [
  {
    "key": {
      "name": "a",
      "kind": "Users",
      "path": [
        "Users",
        "a"
      ]
    },
    "data": {
      "fullname": "a",
      "password": "a",
      "contacts": [
        "bob", "john"
      ]
    }
  },
  {
    "key": {
      "name": "b",
      "kind": "Users",
      "path": [
        "Users",
        "b"
      ]
    },
    "data": {
      "fullname": "b",
      "password": "b",
      "contacts": [
        "john"
      ]
    }
  }
];
console.log(entities);
console.log(entities[1].key.name);
console.log(entities[1].data.contacts[0]);

Answer 2

如果将此JSON对象分配到的变量为entities

然后

entities[ 0 ][ "key" ].name; //will give you name
entities[ 0 ][ "data" ].contacts; //will give you contacts

现在您可以将entities重复为

entities[ counter ][ "key" ].name; //will give you name
entities[ counter ][ "data" ].contacts; //will give you contacts

Answer 3

你有一个阵列。所以你必须使用索引从中读取一个项目。

entities[0]

返回第一个对象。

{
"key": {
  "name": "a",
  "kind": "Users",
  "path": [
    "Users",
    "a"
  ]
},
"data": {
  "fullname": "a",
  "password": "a",
  "contacts": [
    "bob", "john"
  ]
}
}

您可以使用点表示法或括号表示法来读取对象的值。例如，如果您想阅读密钥，请尝试以下方法：

entities[0].key

现在key引用了以下对象：

{
  "name": "a",
  "kind": "Users",
  "path": [
    "Users",
    "a"
  ]
}

所以，如果你想获得name，只需再做一步：

entities[0].key.name

同样适用于contacts：

entities[0].data.contacts

Answer 4

使用entities[ 0 ][ "key" ].name;作为实体是array

Answer 5

您可以尝试这样的事情：

＆＃13;

var json = [{
  "key": {
    "name": "a",
    "kind": "Users",
    "path": [
      "Users",
      "a"
    ]
  },
  "data": {
    "fullname": "a",
    "password": "a",
    "contacts": [
      "bob", "john"
    ]
  }
}, {
  "key": {
    "name": "b",
    "kind": "Users",
    "path": [
      "Users",
      "b"
    ]
  },
  "data": {
    "fullname": "b",
    "password": "b",
    "contacts": [
      "john"
    ]
  }
}]

function getJSONValues(){
  var names = [], contacts = [];
  for (var obj in json){
    console.log(json[obj]);
    
    names.push(json[obj].key.name);
    contacts.push(json[obj].data.contacts.splice(0));
  }
  
  console.log(names, contacts)
}

getJSONValues();

＆＃13;

访问Json数组

5 个答案: