我有以下代码。 (形式在开始时隐藏)
HTML 的
<div1 id="js_sel1">
<p> this is selct 1 </p>
<a class="js_showform" data-id="1" href="#">edit1</a>
</div>
<div2 id="js_sel2">
<p> this is select 2 </p>
<a class="js_showform" data-id="2" href="#">edit2</a>
</div>
<div3 id="js_sel3">
<p> this is select 3 </p>
<a class="js_showform" data-id="3" href="#">edit3</a>
</div>
<form id="js_form" class="js_hide_form">
<p> this is my form </p>
<a class="js_hideform" href="#">save</a>
</form>
的jQuery
$(function() {
var par = $('.js_hide_form');
$(par).hide();
$('.showform').click(function(e) {
e.preventDefault();
var hide_ele = "#js_sel" + $(this).data("id");
var show_ele = "#js_form";
$(hide_ele).hide;
$(show_ele).show;
});
$('.hideform').click(function(e) {
e.preventDefault();
var hide_ele = "#js_form";
var show_ele = "#js_sel" + $(this).data("id");
$(hide_ele).hide;
$(show_ele).show;
});
});
开始时,隐藏表单标记。点击任何编辑(div2的前编辑2),我希望特定的div(ex div2)应该消失,表格应该出现在DIV的特定区域(这里,div2)。
如果你能帮助我,我会非常感激。 TY:)
答案 0 :(得分:2)
请查看此正在运行的代码段:
$(function() {
var par = $('.js_hide_form');
$(par).hide();
$('.js_showform').click(function(e) {
e.preventDefault();
var hide_ele = "#js_sel" + $(this).data("id");
var show_ele = "#js_form";
if($(show_ele).is(":visible"))
return;
$(".js_hideform").data("id",$(this).data("id"));
$(hide_ele).hide();
$(hide_ele).after($(show_ele).detach());
$(show_ele).show();
});
$('.js_hideform').click(function(e) {
e.preventDefault();
var hide_ele = "#js_form";
var show_ele = "#js_sel" + $(this).data("id");
$(hide_ele).hide();
$(show_ele).show();
$("#js_sel3").after($(hide_ele).detach()); //js_sel3 is the id of element after which we want the form should go back
});
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div id="js_sel1">
<p> this is selct 1 </p>
<a class="js_showform" data-id="1" href="#">edit1</a>
</div>
<div id="js_sel2">
<p> this is select 2 </p>
<a class="js_showform" data-id="2" href="#">edit2</a>
</div>
<div id="js_sel3">
<p> this is select 3 </p>
<a class="js_showform" data-id="3" href="#">edit3</a>
</div>
<form id="js_form" class="js_hide_form">
<p> this is my form </p>
<a class="js_hideform" href="#">save</a>
</form>
&#13;
答案 1 :(得分:0)
纠正你的div并尝试js:
<div id="js_sel1">
<p> this is selct 1 </p>
<a class="js_showform" data-id="1" href="#">edit1</a>
</div>
<div id="js_sel2">
<p> this is select 2 </p>
<a class="js_showform" data-id="2" href="#">edit2</a>
</div>
<div id="js_sel3">
<p> this is select 3 </p>
<a class="js_showform" data-id="3" href="#">edit3</a>
</div>
<form id="js_form" class="js_hide_form">
<p> this is my form </p>
<a class="js_hideform" href="#">save</a>
</form>
JS:
$(function() {
$('div[id^="js_sel"] .js_showform').on('click',function(){
var parent = $(this).closest('div[id^="js_sel"]');
$('#js_form').clone().insertBefore(parent);
parent.hide();
parent.prev().show();
});
$('body').on('click','.js_hide_form a',function(){
console.log(this);
$(this).parent().next().show();
$(this).parent().hide();
});
});
https://jsfiddle.net/9h8r7akt/1/
或:
$(function() {
$('div[id^="js_sel"] .js_showform').on('click',function(){
var parent = $(this).closest('div[id^="js_sel"]');
$('#js_form').detach().insertBefore(parent);
$('div[id^="js_sel"] ').show();
parent.hide();
parent.prev().show();
});
$('body').on('click','.js_hide_form a',function(){
console.log(this);
$('div[id^="js_sel"]').show();
$(this).parent().hide();
});
});