Question

我尝试将Textview的值更改为我正在查询解析的某些信息，但出于某种原因，.setText没有生效。

我尝试使用Google搜索，但.getString也不起作用。我是Parse任何建议的新手？

我的代码如下：

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.TextView;

import com.parse.FindCallback;
import com.parse.GetCallback;
import com.parse.ParseException;
import com.parse.ParseObject;
import com.parse.ParseQuery;

import org.w3c.dom.Text;

import java.util.List;


/**
* A simple {@link Fragment} subclass.
 */
public class productDetail extends Fragment {


public productDetail() {
    // Required empty public constructor
}






@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {

    final View theView = inflater.inflate(R.layout.fragment_product_detail, container, false);

    final TextView productNameLabel = (TextView) theView.findViewById(R.id.productNameTextView);
    final TextView productDetailsLabel = (TextView) theView.findViewById(R.id.productDetails);
    final TextView shippingFeeLabel = (TextView) theView.findViewById(R.id.shippingFee);
    final TextView productPriceLabel = (TextView) theView.findViewById(R.id.productPrice);
    final TextView productNumberOfReviewsLabel = (TextView) theView.findViewById(R.id.productNumberOfReviews);

    final String chosenProduct = getArguments().getString("productName");
    Log.i("AppInfo", chosenProduct);

    ParseQuery<ParseObject> query = new ParseQuery<ParseObject>("Inventory");
    query.whereEqualTo("productName", chosenProduct);
    query.getFirstInBackground(new GetCallback<ParseObject>() {
        @Override
        public void done(ParseObject parseObject, ParseException e) {
            if (parseObject == null) {

                Integer fee = parseObject.getInt("ShippingFee");
                Integer review = parseObject.getInt("numberOfReviews");
                String information = parseObject.get("information").toString();
                Integer price = parseObject.getInt("price");


                productNameLabel.setText(chosenProduct);
                productDetailsLabel.setText(String.valueOf(information));
                shippingFeeLabel.setText(String.valueOf(fee));
                productPriceLabel.setText(String.valueOf(price));
                productNumberOfReviewsLabel.setText(String.valueOf(entries));

            }

        }
    });




    // Inflate the layout for this fragment
    return theView;
}

}

Answer 1

if语句中的所有内容都会在输入时抛出NullPointerException :)

将if语句更改为此

padding-bottom:calc(33.3333333% - 1px);

或许你的意思是这个？

if (parseObject != null)

Android setText无法在TextView上运行

1 个答案: