Question

我收集了2种不同的对象。

我试图根据字符串属性做一个.Intersect ......

public class EmployeeDto
{
    public string SSN { get; set; }
    public DateTime HireDate { get; set; }
}


public class PersonDto
{
    public string SocialSecurityNumber { get; set; }
    public string Name { get; set; }
}

尝试：

            ICollection<EmployeeDto> empsColl = new List<EmployeeDto>();
            empsColl.Add(new EmployeeDto() { SSN = "222-22-2222", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "333-33-3333", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "444-44-4444", HireDate = DateTime.Now });
            empsColl.Add(new EmployeeDto() { SSN = "555-55-5555", HireDate = DateTime.Now });


            ICollection<PersonDto> pers = new List<PersonDto>();

            pers.Add(new PersonDto() { SocialSecurityNumber = "333-33-3333", Name = "John" });
            pers.Add(new PersonDto() { SocialSecurityNumber = "444-44-4444", Name = "Mary" });



            ICollection<EmployeeDto> overlap1 = empsColl.Where(api => api.SSN.Any(val => val.Equals(pers.Any(cl => cl.SocialSecurityNumber.Equals(val))))).ToList();

 ICollection<EmployeeDto> overlap2 = empsColl.Where(api => api.SSN.Equals(pers.Any(per => per.SocialSecurityNumber.Equals(api.SSN, StringComparison.OrdinalIgnoreCase)))).ToList();



            foreach (EmployeeDto emp in overlap1)
            {
                Console.WriteLine(emp.SSN);
            }

所需的结果是ICollection<EmployeeDto>，当然包含333-33-3333和444-44-4444的EmployeeDto对象。

感谢。

Answer 1

以下是如何做到的：

public Dimension getSize()

Answer 2

我认为这样做会

    empsColl.Where(ec => pers.Select(p => p.SocialSecurityNumber).Contains(ec.SSN)));

Answer 3

这应该有效

    var result =  empsColl.Where(x => pers.Any(y=> string.Compare(y.SocialSecurityNumber, x.SSN) == 0));

基于不同名称的字符串属性交叉2种不同的集合

3 个答案: