您好我正在尝试使用基于Ajax返回的结果返回的jQuery创建可排序列表。这就是我所拥有的。
在我的settings.php页面上,我的<head>
代码中包含以下内容:
<script type="text/javascript">
$(document).ready(function () {
$('#sportsort').sortable({
axis: 'y',
update: function (event, ui) {
var data = $('#sportsort').sortable('serialize');
$('#test').text(data);
$.post("actions.php?action=updatesort",data,function(theResponse){
$("#sportsavemessage").html(theResponse);
$('#sportsavemessage').css("color","green");
$('#sportsavemessage').css("float","right");
});
}
});
});
</script>
<script type="text/javascript">
function updateSortable() {
$('ul#leaguesort').sortable({
axis: 'y',
stop: function(event, ui) {
var data2 = $('ul#leaguesort').sortable('serialize');
console.log(data2);
$('#test').text(data2);
$.post("actions.php?action=updatesort",data2,function(theResponse) {
$("#leaguesavemessage").html(theResponse);
$('#leaguesavemessage').css("color", "green");
$('#leaguesavemessage').css("float", "right");
});
}
});
};
</script>
<script>
function showLeagues(str) {
if (str=="") {
document.getElementById("leagues").innerHTML="";
return;
}
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("leagues").innerHTML=xmlhttp.responseText;
updateSortable();
}
}
xmlhttp.open("GET","get_leagues.php?q="+str,true);
xmlhttp.send();
}
</script>
在settings.php正文中,我有以下部分:
<div class="box span6">
<div style="padding-left: 12px;padding-top:10px;padding-bottom:5px">Choose Sport to view leagues
<select style="padding-top: 5px;" onchange="showLeagues(this.value)" >
<option>Select a Sport</option>
<?php
foreach ($conn->query('SELECT * FROM site_settings WHERE setting_name="sports" ORDER BY sort_order') as $sports) {
echo '<option value="'.$sports['setting_option'].'">'.$sports['setting_option']."</option>";
}
?>
</select>
</div>
<div class="box-header">
<h2>List of Events</h2> <span id="leaguesavemessage"></span>
</div>
<div class="box-content">
<div id="leagues"></div>
</div>
</div>
如你所见,我有一个带有下拉框的div部分。从此下拉框中选择后,该值将发送到get_leagues.php页面,并以列表格式返回一些项目。然而,尽管我已经应用了jQuery可排序标记,但这些项目根本不会拖放它们。这是get_leagues.php文件。
<?php
include "header.php";
$query = "SELECT * FROM site_settings WHERE setting_name ='leagues' AND setting_option=:sport";
$stmt = $conn->prepare($query);
$stmt->bindParam(":sport", $_GET['q']);
$stmt->execute();
$leagues = $stmt->fetchAll();
echo '<ul class="dashboard-list metro" id="leaguesort">';
$i = 1;
foreach ($leagues as $league_new) {
echo '<li value="id_'.$league_new['id'].'"><i class="icon-caret-right"></i>'.$league_new['setting_option_value'].'</li>';
$i++;
}
echo '</ul>';
?>
下拉工作正常,我将正确的项目返回到我的列表中,但是我无法拖动和排序这些项目。我尝试将排序脚本移动到get_legaues文件无济于事。我尝试切换.ready为联赛刷新和改变但也无济于事。有人指出我正确的方向让这个工作。正如您在我的帖子中所看到的,我也希望如果可能的话立即更新数据库。非常感谢帮助!
答案 0 :(得分:0)
两件事:
<强> 1 强> 您的代码容易受到SQL注入攻击,这是一种严重且常被利用的安全风险。请在此处阅读:https://www.owasp.org/index.php/SQL_Injection
<强> 2 强>
问题可能是由于您只运行$('#leaguesort').sortable
函数一次(当页面加载时)和运行时没有#leaguesort
,因此不会发生任何事情。您需要做的是将$('#leaguesort').sortable
提取到自己的函数中,然后在每次获得结果时调用:
function updateSortable() {
$('#leaguesort').sortable({
axis: 'y',
update: function(event, ui) {
var data = $('#leagues').sortable('serialize');
$.post("actions.php?action=leaguesort", data, function(theResponse) {
$("#leaguesavemessage").html(theResponse);
$('#leaguesavemessage').css("color", "green");
$('#leaguesavemessage').css("float", "right");
});
}
});
}
然后在
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("leagues").innerHTML=xmlhttp.responseText;
updateSortable(); // ADDED THIS LINE
}