Question

我试图运行该功能，但我不知道如何让它运行。我试着点击并为每个select.all创建单独的函数。我希望函数做的是当我选择将段落的值更改为下面的选项时。请帮忙。

<select id="Providers"  onchange="ProviderChanger()">
    <option value="Empty" id="Empty" name="Empty">Please Select     Provider</option> 
    <option value="Du1" id="Du1" name="Du1">Du 052</option>
    <option value="Du2" id="Du2" name="Du2">Du 055</option>
    <option value="Etisilat1" name="Etisilat1" id="Etisilat1">Etisilat 050</option>
    <option value="Etisilat2" name="Etisilat2" id="Etisilat2">Etisilat 056</option>
    <option value="Office" name="Office" id="Office">House/Office 04</option>
</select>

function ProviderChanger()
{
  var ProviderValue = document.getElementById("Provider").value;
  alert(ProviderValue);
  if (ProviderValue == "Du1")
    document.getElementById("Provider").innerHTML = "+971-55";
  else if (ProviderValue == "Du2")
    document.getElementById("Provider").innerHTML = "+971-52";
  else if (ProviderValue == "Etisilat1")
    document.getElementById("Provider").innerHTML = "+971-50";
  else if (ProviderValue == "Etisilat2")
    document.getElementById("Provider").innerHTML = "+971-56";
  else if (ProviderValue == "Office")
    document.getElementById("Provider").innerHTML = "+971-04";
  else
    document.getElementById("Provider").innerHTML = "";
}

Answer 1

不应该这样：

var ProviderValue = document.getElementById("Providers").value;

是这样的：

// str is a global variable, so it is safe to reference it with &
string str = str1 + '\0' + str2 + '\0' + str3 + '\0' + str4;
func_that_needs_null_separated_str(&str[0]);

Answer 2

您是否在功能周围设置了脚本标签？你错过了你的Id的结尾。

的document.getElementById（ “提供者”）

onchange并选择不工作

2 个答案: