Question

我想创建以下xml

<BookStore>
  <Book>
    <Name></Name>
    <Author></Author>
    <Price></Price>
  </Book>
  <Book>
    <Name></Name>
    <Author></Author>
    <Price></Price>
  </Book>
</BookStore>

来自

List<XElement> Book= xdoc.XPathSelectElements("s0:Name| s0:Author| s0:Price", namespaceManager).ToList();

我在以下地方受到打击：

XNamespace s0 = "urn:service.Bookstore.com";
XElement root=new XElement(s0 + "BookStore",
                 new XElement("Book",Book,
                              );
XDocument result = new XDocument(root);

但这使得xml结构为

<BookStore>
  <Book>
    <Name></Name>
    <Author></Author>
    <Price></Price>
    <Name></Name>
    <Author></Author>
    <Price></Price>
  </Book>
</BookStore>

请帮助我获得预期的输出。因为基本的xml结构看起来像这样

<BookStore>
  <Book>
    <Name></Name>
    <Author></Author>
    <Price></Price>
    <Name></Name>
    <Author></Author>
    <Price></Price>
  </Book>
</BookStore>

但我想把它作为

的两个独立实例

Answer 1

听起来你基本上需要获取元素列表并将它们分组为3个元素的组，将每个组放在Book元素中：

// The name/author/price elements you're already getting
var elements = ...; 
var groups = elements.Select((value, index) => new { value, index })
                     .GroupBy(pair => pair.index / 3, pair => pair.value);
XNamespace s0 = "urn:service.Bookstore.com";
XDocument result = new XDocument(new XElement(s0 + "BookStore",
    groups.Select(g => new XElement("Book", g))));

Answer 2

试一试：

XElement xElement = new XElement("BookStore", new XElement("Book", new XElement("Name", "value"), new XElement("Author", "value"), new XElement("Price", "value")));

xElement.Save("Location.xml");

使用linq从List <xelement>创建节点

2 个答案: