Question

我正在尝试在列上找到两个字符之间的子字符串例如

该列有

Bought ____ by manager
Bought ____ by employee
Bought ____ by other

空白总是在Bought和by之间。我想把空白中的值分开？任何人都可以帮助我

Answer 1

您的问题有两个标记MySQL/SQL Server，如果您有SQL Server，则可以使用SUBSTRING和PATINDEX：

CREATE TABLE #tab(col VARCHAR(100));

INSERT INTO #tab
SELECT 'Bought AAAAAAAAA by manager'
UNION ALL SELECT 'Bought BB by employee'
UNION ALL SELECT 'Bought C by other';

SELECT col,
 SUBSTRING(col, 8, PATINDEX('% by%', col)-8)
FROM #tab;

的 LiveDemo

输出：

╔═════════════════════════════╦═══════════╗ ║ col ║ result ║ ╠═════════════════════════════╬═══════════╣ ║ Bought AAAAAAAAA by manager ║ AAAAAAAAA ║ ║ Bought BB by employee ║ BB ║ ║ Bought C by other ║ C ║ ╚═════════════════════════════╩═══════════╝

起点固定为8，长度计算为by减去固定8之前的空间位置。
使用MySQL的
LOCATE版本：

SELECT col, SUBSTRING(col, 8, LOCATE(' by', col)-8) AS result FROM tab;

的 SqlFiddleDemo

Answer 2

SUBSTRING（表达式，开始，长度）

来源：https://msdn.microsoft.com/en-us/library/ms187748.aspx

Answer 3

使用下面提到的代码： -

select left(col1,charindex(' ',col1)-1) as val1, ltrim(substring(col1,charindex(' ',col1),len(col1))) as val2
from mytable

如何查找整列的子字符串

3 个答案: