Mongoose模式方法是“不是函数”

Question

我的模型看起来像这样，但当我尝试使用app.controller('myController', function($scope) { $scope.myMethod = function() {}; //Not callable from controller passed to directive this.myMethod = function() {}; //IS callable from controller passed to directive }); 时，它会显示verifyPassword

TypeError: user.verifyPassword is not a function

我这样使用它。

const User = new mongoose.Schema({
  name: {
    type: String,
    required: true
  },
  password: {
    type: String,
    required: true
  },
  avatar: String,
  token: String,
  role: String,
  permissions: Array,
  email: {
    type: String,
    unique: true,
    required: true
  },
  joined: {
    type: Number,
    default: ( new Date() * 1 )
  }
})

User.methods.verifyPassword = function (password) {
  return bcrypt.compare(password, this.password)
}

Answer 1

Mongo＆＃34;发现＆＃34;返回结果的可迭代游标（可能没有）。如果您希望仅获得一个结果，请尝试＆＃34; findOne＆＃34;代替。这将返回一个文档。