当我按btn时,我的主要形式是我用showDialog()函数打开新表单, 当我按下主表单时,我需要将两个表单一起移动,因为它们共享 设计。 如何将它们一起移动到主窗体并移动它或者我按下form2然后移动它? 很多任何建议。
答案 0 :(得分:5)
您可以创建一个单独的类来管理表单连接和事件处理。
class FormConnector
{
private Form mMainForm;
private List<Form> mConnectedForms = new List<Form>();
private Point mMainLocation;
public FormConnector(Form mainForm)
{
this.mMainForm = mainForm;
this.mMainLocation = new Point(this.mMainForm.Location.X, this.mMainForm.Location.Y);
this.mMainForm.LocationChanged += new EventHandler(MainForm_LocationChanged);
}
public void ConnectForm(Form form)
{
if (!this.mConnectedForms.Contains(form))
{
this.mConnectedForms.Add(form);
}
}
void MainForm_LocationChanged(object sender, EventArgs e)
{
Point relativeChange = new Point(this.mMainForm.Location.X - this.mMainLocation.X, this.mMainForm.Location.Y - this.mMainLocation.Y);
foreach (Form form in this.mConnectedForms)
{
form.Location = new Point(form.Location.X + relativeChange.X, form.Location.Y + relativeChange.Y);
}
this.mMainLocation = new Point(this.mMainForm.Location.X, this.mMainForm.Location.Y);
}
}
现在,您所要做的就是实例化FormConnector并使用您要连接的表单调用ConnectForm方法。
答案 1 :(得分:0)
主要成分是表单“Top
,Left
,Location
和Width
属性。假设您有两个表单的引用,称为form1
和form2
。您可以像这样重新定位窗口:
form2.Location = new Point(form1.Left + form1.Width, form1.Top);
结果是两个形式,顶部对齐,右侧是form2。
参考: