Question

如何从Python smtplib库中捕获调试输出？

这是我的测试程序：

import smtplib
s = smtplib.SMTP("mx10.comcast.com")
s.set_debuglevel(1)
s.sendmail("no-such-sender@comcast.com",["no-such-receiver@comcast.com"],"""
from: no-such-sender@comcast.com
to: no-such-receiver@comcast.com
subject: no such message

This message won't be delivered to anybody.
""")

这是输出：

send: 'ehlo dance.local\r\n'
reply: '250-mx10.comcast.com says EHLO to 129.6.220.67:57015\r\n'
reply: '250-SIZE 40000000\r\n'
reply: '250-PIPELINING\r\n'
reply: '250-ENHANCEDSTATUSCODES\r\n'
reply: '250-8BITMIME\r\n'
reply: '250 XXXXXXXA\r\n'
reply: retcode (250); Msg: mx10.comcast.com says EHLO to 129.6.220.67:57015
SIZE 40000000
PIPELINING
ENHANCEDSTATUSCODES
8BITMIME
XXXXXXXA
send: 'mail FROM:<no-such-sender@comcast.com> size=137\r\n'
reply: '250 2.0.0 MAIL FROM accepted\r\n'
reply: retcode (250); Msg: 2.0.0 MAIL FROM accepted
send: 'rcpt TO:<no-such-receiver@comcast.com>\r\n'
reply: '550 5.1.1 Recipient address rejected: {Gateway}\r\n'
reply: retcode (550); Msg: 5.1.1 Recipient address rejected: {Gateway}
send: 'rset\r\n'
reply: '250 2.0.0 RSET OK\r\n'
reply: retcode (250); Msg: 2.0.0 RSET OK
Traceback (most recent call last):
  File "/Users/simsong/x.py", line 11, in <module>
    """)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/smtplib.py", line 742, in sendmail
    raise SMTPRecipientsRefused(senderrs)
smtplib.SMTPRecipientsRefused: {'no-such-receiver@comcast.com': (550, '5.1.1 Recipient address rejected: {Gateway}')}

我希望输出变量output。具体来说，我想要所有以send:和reply:开头的行。

Answer 1

可以通过将stderr重定向到文件来完成：

import tempfile, smtplib, os, sys

# Find an available file descriptor                                                                                              
t = tempfile.TemporaryFile()
available_fd = t.fileno()
t.close()

# now make a copy of stderr                                                                                                      
os.dup2(2,available_fd)

# Now create a new tempfile and make Python's stderr go to that file                                                             
t = tempfile.TemporaryFile()
os.dup2(t.fileno(),2)

# Now run the task that logs to stderr                                                                                           
s = smtplib.SMTP("mx10.comcast.com")
s.set_debuglevel(1)
s.sendmail("no-such-sender@comcast.com",["no-such-receiver@comcast.com"],"""                                                     
from: no-such-sender@comcast.com                                                                                                 
to: no-such-receiver@comcast.com                                                                                                 
subject: no such message                                                                                                         

This message won't be delivered to anybody.                                                                                      
""")

# Grab the stderr from the temp file                                                                                             
sys.stderr.flush()
t.flush()
t.seek(0)
stderr_output = t.read()
t.close()

# Put back stderr                                                                                                                
os.dup2(available_fd,2)
os.close(available_fd)


# Finally, demonstrate that we have the output:                                                                                  
print("STDERR:")
count = 0
for line in stderr_output.decode('utf-8').split("\n"):
    count += 1
    print("{:3} {}".format(count,line))

Answer 2

研究错误：

a = None
try:
    s.sendmail("no-such-sender@comcast.com"   ["no-suchreceiver@comcast.com"],"""
    from: no-such-sender@comcast.com
    to: no-such-receiver@comcast.com
    subject: no such message

    This message won't be delivered to anybody.
    """)
except smtplib.SMTPRecipientsRefused as e:
    a = e

现在您可以看看如何提取它：

a.args

（{＆＃39; no-such-receiver@comcast.com'：（550， b＆＃39; 5.1.1收件人地址被拒绝：{Gateway}＆＃39;）}，）

a.args[0]['no-such-receiver@comcast.com'][1]

b＆＃39; 5.1.1收件人地址被拒绝：{Gateway}＆＃39;

这是你的消息！

所以提取它：

message = None
try:
    s.sendmail("...")

except smtplib.SMTPException as e:
    message = e.args[0]['no-such-receiver@comcast.com'][1]

捕获Python smtplib的调试输出

2 个答案: