我创建了一个运行的查询...实际上只需要9秒就可以自行运行。但是......当我尝试将它用作左或右连接语句中的主表时，会导致该查询失败（超时）。
我相信它是因为我在桌子上打了14次左右（表格中的500k行）来比较某些行。我相信有一种方法可以将其合并为2个全表扫描......但我不知道如何。
以下是我如何检查两种情况的示例...我这样做了大约4-5次。
谢谢！
left join
--SUM THE DURATION OF LUNCHES DURING PTO
(SELECT o.employee, convert(date, o.start_time) as createdate,
SUM(DATEDIFF (
minute,
CASE WHEN S.START_time < O.START_time THEN O.START_time
ELSE S.START_time
END,
CASE WHEN S.STOP_time > O.STOP_time THEN O.STOP_time
ELSE S.STOP_time
END
)) as unplanned_superstate
FROM table1 O -- LUNCH CONTAINERS
JOIN table1 S -- PTO CONTAINERS
ON O.Employee = S.Employee
AND s.START_time <= o.STOP_time
AND S.STOP_time >= o.START_time
WHERE
O.code IN ('LUNCH')
AND S.code IN ('CODE1','CODE2','CODE3','CODE4')
group by o.employee, convert(date, o.start_time)
) ul
on ul.employee = segments.employee and segments.createdate = ul.createdate
left join
--SUM THE DURATION OF LUNCHES DURING SHIFT
(SELECT o.employee, convert(date, o.start_time) as createdate,
SUM(DATEDIFF (
minute,
CASE WHEN S.START_time < O.START_time THEN O.START_time
ELSE S.START_time
END,
CASE WHEN S.STOP_time > O.STOP_time THEN O.STOP_time
ELSE S.STOP_time
END
)) shift_superstate
FROM table1 O -- LUNCH CONTAINERS
JOIN table1 S -- SHIFT CONTAINERS
ON O.Employee = S.Employee
AND S.START_time <= O.STOP_time
AND S.STOP_time >= o.START_time
WHERE
O.code = 'LUNCH'
AND S.code IN ('SHIFT')
group by o.employee, convert(date, o.start_time)
) ul2
on ul2.employee = segments.employee and segments.createdate = ul2.createdate