Question

嗨，大家好我要显示一个ListView（下面的代码）在片段里面！
怎么做。我已经搜索过但我没有找到解决这个问题的任何东西。

谢谢大家的帮助:-D

ExperimentsList.java：

public class ExperimentsList extends AppCompatActivity {

public ListView lv1;
public String[] listentext = {"Cola&Mentos","2","3","4"};



@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_experiments_list);

    android.support.v7.app.ActionBar supportActionBar = getSupportActionBar();
    supportActionBar.setDisplayHomeAsUpEnabled(true);

    lv1 = (ListView) findViewById(R.id.listView);

    ArrayAdapter<String> listenadapter = new ArrayAdapter<>(ExperimentsList.this, android.R.layout.simple_list_item_1, listentext);
    lv1.setAdapter(listenadapter);
    lv1.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg0, View view, int arg2, long arg3) {

            switch (lv1.getPositionForView(view)) {

                case 0:{
                    Intent myIntent = new Intent(ExperimentsList.this, ColaMentos.class);

                    final int result = 1;

                    ExperimentsList.this.startActivity(myIntent);

                }





            }



        }
    });
}

}

Answer 1

我假设您要在选项卡下的viewpager中显示列表。为此，您可以获取viewpager并为其设置FragmentPagerAdaptor，它从getItem方法返回ListFragment的实例。

mViewPager = (ViewPager) findViewById(R.id.container);
mSectionsPagerAdapter = new SectionsPagerAdapter(getSupportFragmentManager());
mViewPager.setAdapter(mSectionsPagerAdapter);

在寻呼机适配器中：

  public class SectionsPagerAdapter extends FragmentPagerAdapter {
        @Override
                public Fragment getItem(int position) {
                    return MyListFragment.newInstance("");
                }

            .....
            .....
    }

您可以编写ListFragment的实现来显示列表数据。

Answer 2

您应该将activity_experiments_list更改为：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent">

    <fragment
        android:id="@+id/one_frag"
        android:name="biz.progmar.testapp.ListViewFragment"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        />
</LinearLayout>

添加ListViewFragment.class：

public class ListViewFragment extends Fragment{
    @Nullable
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        String[] listentext = {"Cola&Mentos","2","3","4"};
        ArrayAdapter<String> listenadapter = new ArrayAdapter<>(getActivity(), android.R.layout.simple_list_item_1, listentext);
        //load the simple_layout.xml which contains only one ListView.
        View view = inflater.inflate(R.layout.simple_layout,container,false);
        //use id="lv1" to capture the ListView
        ListView listView = (ListView) view.findViewById(R.id.lv1);
        //set the adapter
        listView.setAdapter(listenadapter);
        return view;
    }

}

让inflater膨胀simple_layout：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent">

    <ListView
        android:id="@+id/lv1"
        android:layout_width="match_parent"
        android:layout_height="match_parent">
    </ListView>
</LinearLayout>

然后，您可以在活动布局中看到它还有一个ListView

如何在片段中显示Listview

2 个答案: