我试图将typeahead
与Parse.com结果一起使用。我认为Parse
会返回JSON
个对象,但似乎以下方法无法识别它。谁能发现什么错了?或者可能有更简单的方法使它工作(最后我希望能够搜索每个对象的两个字段)。
到目前为止,我已经达到了这一点(感谢:https://github.com/bassjobsen/Bootstrap-3-Typeahead):
function queryListy(){
Parse.Cloud.run('queryList', {}, {
success: function(result) {
var $input = $('#query');
$input.typeahead({source:result,
autoSelect: true});
$input.change(function() {
var current = $input.typeahead("getActive");
if (current) {
// Some item from your model is active!
if (current.name == $input.val()) {
// This means the exact match is found. Use toLowerCase() if you want case insensitive match.
} else {
// This means it is only a partial match, you can either add a new item
// or take the active if you don't want new items
}
} else {
// Nothing is active so it is a new value (or maybe empty value)
}
});
},
error: function(error) {
console.log(error);
}
});
}
当我放[{id: "someId1", name: "Display name 1"}, {id: "someId2", name: "Display name 2"}]
代替result
时,它的工作基本机制似乎是正确的。
答案 0 :(得分:2)
Parse不会以您可以直接使用的形式返回对象。您需要在所需的每个房产上致电get
:
var mappedObjects = [];
result.forEach(function(parseObject){
mappedObjects.push({
id: parseObject.id, //id is special, you don't need get
name: parseObject.get("name"), //generic fields need get
});
});
$input.typeahead({source:mappedObjects, ...
如果您愿意,可以在云代码中执行此映射,以便客户端代码不需要。